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prisoha [69]
3 years ago
12

A cicular pond has a radius of 3 feet. What is the approximate distance around the edge of pond?

Mathematics
1 answer:
SashulF [63]3 years ago
8 0
The answer is C do you need to know why?
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When a figure is translated, its orientation remains the same or changes ?
Leviafan [203]
No it does not change it is a imaginary like used to move a figure. Nor does it move when it is rotated
6 0
3 years ago
Use the given values of n and p to find the minimum usual value μ−2σ and the maximum usual value μ+2σ. Round to the nearest hund
lbvjy [14]

Answer:

μ−2σ = 1,089.26

μ+2σ = 1,097.62

Step-by-step explanation:

The standard deviation of a sample of size 'n' and proportion 'p' is:

\sigma=\sqrt{\frac{p*(1-p)}{n} }

If n=1139 and p =0.96, the standard deviation is:

\sigma=\sqrt{\frac{p*(1-p)}{n}}\\\sigma = 0.001836

The minimum and maximum usual values are:

\mu-2\sigma = (p-2\sigma)*n\\\mu+2\sigma = (p+2\sigma)*n

\mu-2\sigma = (0.96-2*0.001836)*1139\\\mu-2\sigma = 1,089.26\\\mu+2\sigma = (0.96+2*0.001836)*1139\\\mu+2\sigma = 1,097.62

5 0
2 years ago
Find the probability of spinning an A 3 times
Dima020 [189]
If the probability of spinning an A once is 1/12, then the probability of spinning an A 3 times is 3 × 1/12.

3 × 1/12 = 3/36

Simplify

3/36 = 1/12
6 0
3 years ago
HELP PLEASE!!! Thanks!
Irina18 [472]

Answer:

2) \frac{\sqrt{77}}{11}

3) 5√2

Step-by-step explanation:

Simplest radical form of an expression is the expression in radical so that there are no more square roots, cube roots, 4th roots, etc left to find, after rationalising the denominator ( if needed ).

2. Here the given expressions,

\frac{\sqrt{7}}{\sqrt{11}}

For rationalising the denominator multiply both numerator and denominator by √11,

\frac{\sqrt{77}}{11}

3. given expression,

\sqrt{50}

=\sqrt{25\times 2}

=\sqrt{25}\times \sqrt{2}   (\because \sqrt{ab}=\sqrt{a}\sqrt{b})

=5\sqrt{2}

8 0
3 years ago
Which of the following statements best describes the graph of −5x + 2y = 1?
Nina [5.8K]

First, we determine that the given equation in this item is a linear equation. Thus, it should be a straight line. With this, we are left with the third and fourth choice. Then, we substitute the given data points to the equation and see if the points satisfy the given.

Choice 3:

<span>            (1,3)   :    (-5)(1) + (2)(3) = 1   TRUE</span>

<span>            (3,8)   :    (-5)(3) + 2(8) = 1      TRUE</span>

<span>            (-3,-7) :    (-5)(-3) + (2)(-7) = 1 TRUE</span>

 

Choice 4:

<span>            (4,-3)  :  (-5)(4) + (2)(-3) ≠ 1     FALSE</span>

<span>            (-1,2)   : (-5)(-1) + (2)(2) ≠ 1     FALSE</span>

<span>            (-4,5)   : (-5)(-4) + (2)(5) ≠ 1    FALSE</span>

 

<span>Thus, the answer is the third choice.</span>

5 0
3 years ago
Read 2 more answers
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