A cicular pond has a radius of 3 feet. What is the approximate distance around the edge of pond?

Simplify the expression (3 + 6x) - 2 (x + 1 ) + 5.

balandron [24]

Step 1 :

Equation at the end of step 1 :

((6x + 3) - 2 • (x + 1)) + 5
Step 2 :

Step 3 :

Pulling out like terms :

3.1 Pull out like factors :

4x + 6 = 2 • (2x + 3)

Final result :

2 • (2x + 3)

7 0

3 years ago

Can anyone help please!<br> Ixl geometry

Aliun [14]

I hope this helps you

IJH~IKL

IJ/IK=JH/KL=IH/IL

2.1/2.1+0.9=2.8/x

2.1/3=2.8/x

x=2.8*3/2.1

x=4

8 0

3 years ago

Find the exact value by using a half angle identity.tan 75°

kramer

The trigonometric function is given as

$\tan 75^{\circ}$

Apply the half angle identity to find the value of tan 75 ,

$\tan (\frac{u}{2})=\frac{\sin u}{1+\cos u}$

Here,

$\tan (\frac{150^{\circ}}{2})=\frac{\sin150^{\circ}}{1+cos150^{\circ}}$ $\tan (75^{\circ})=\frac{\frac{1}{2}}{1-\frac{\sqrt[]{3}}{2}}=\frac{\frac{1}{2}}{\frac{2-\sqrt[]{3}}{2}}^{}$ $\tan 75^{\circ}=\frac{1}{2-\sqrt[]{3}}$

Now rationalize the function.

$\tan 75^{\circ}=\frac{1}{2-\sqrt[]{3}}\times\frac{2+\sqrt[]{3}}{2+\sqrt[]{3}}=\frac{2+\sqrt[]{3}}{4-3}=\frac{2+\sqrt[]{3}}{1}$

Again simplify the trigonometric function,

$\tan 75^{\circ}=2+1.732=3.732$

Hence the answer is 3.732.

5 0

1 year ago

A machine operation produces bearings whose diameters are normally distributed, with a mean of 0.497 inch and a standard deviati

eduard

Mean = 0.497 in, SD = 0.003 in
Required diameter ranges between 0.496 in and 0.504 in
Anything other diameter obtained is not acceptable.

That is;
P(x<0.496) and P(x>0.504) are not acceptable.

Now,
P(x<0.496) = P(Z< (0.496-0.497)/0.003)) = P(Z<-0.33)
From Z tables, P(Z<-0.33) = 0.3707

Similarly,
P(x>0.504) = P(Z> (0.504-0.497)/0.003)) = P(Z>2.33)
From Z tables, P(Z>2.33) = 1-0.9901 = 0.0099

Therefore, unacceptable proportion = P(x<0.496)+P(x>0.504) = 0.3707+0.0099 = 0.3806 or 38.06%

6 0

3 years ago

Find three consecutive integers such as two times the first integer, plus three times the second integer, minus the third intege

NikAS [45]

The three consecutive integers are 5, 6, and 7.

What are consecutive integers?

Whole numbers that follow one another without a gap are known as consecutive integers. A few examples of consecutive integers are 15, 16, and 17, 1,2 and 3, and so on.

Finding the Consecutive Integers

Let the three consecutive integers be a, a + 1, and a + 2.

These three consecutive integers are to be such that two times the first integer when added to three times the second integer minus the third integer, it is equal to 21.

⇒ 2a + 3(a+1) - (a+2) = 21

2a + 3a + 3 - a -2 = 21

5a - a + 3 - 2 = 21

4a + 1 = 21

4a = 20

a = 20/4

a = 5

∴ a+1 = 5+1

a+1 = 6

And, a+2 = 5 + 2

a +2 =7

Hence, the three consecutive integers come out to be 5, 6, and 7

Learn more about consecutive integers here:

brainly.com/question/1767889

#SPJ4

8 0

2 years ago