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likoan [24]
3 years ago
12

19,9,10 can be the measures of the sides of a triangle?

Mathematics
1 answer:
lbvjy [14]3 years ago
6 0

Answer:

no

Step-by-step explanation:

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Viktor [21]

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6

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divide

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2 years ago
Simplify completely 8x^3 ÷ 6x^2 - 4x / -2x
artcher [175]

Answer:

Simplified form is -(\frac{8x^{3}}{3x-2}).

Step-by-step explanation:

The given expression is 8x^{3}\div \frac{6x^{2}-4x}{-2x}

We can rewrite the given expression as = 8x^{3}\times (-\frac{2x}{{6x^{2}-4x}})

Further simplification of the expression gives =\frac{-16x^{4}}{6x^{2}-4x}

=\frac{-16x^{4}}{2x(3x-2)}

=-(\frac{8x^{3}}{3x-2})

So the simplified of the given expression is =[tex]-(\frac{8x^{3}}{3x-2})

3 0
3 years ago
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12x15y=4140; x+y= ? <br> solve.
Semenov [28]

Answer: The number of $12 tickets and $15 sold are 120 and 180 respectively.

Step-by-step explanation:

The given equation is:

12x + 15y = 4140             .....(1)

Where,

x stands for $12 tickets and y stands for $15 tickets

According to the question:

x + y = 300           ....(2)

Now solving equation 1 and 2.

From equation 2:

x = 300 - y

Now putting this expression in equation 1.

12x + 15y = 4140

12(300 - y) + 15y = 4140

3600 - 12y + 15y = 4140

3600 + 3y = 4140

3y = 4140 - 3600

3y = 540

y = 180

And,

x = 300 - y = 300 - 180 = 120

The number of $12 tickets sold = x = 120

The number of $15 tickets sold = y = 180

Thus, the number of $12 tickets and $15 sold are 120 and 180 respectively.

4 0
3 years ago
What are the vertex focus and directrix of a parabola with equation x=y^2+14y-2
zimovet [89]
This is a sideways opening parabola, opening to the right to be more specific, since the leading coefficient is a positive 1.  The rule for a focus and a directrix is that they are the same number of units from the vertex (in other words, the vertex is dead center between them), and that the vertex is on the same axis that the focus is.  We need to find the vertex then to determine what the focus and the directrix are.  We will complete the square on that to find the vertex.  Begin by setting it equal to 0, then move the 2 over by addition to get y^2+14y=2.  Now we will complete the square on the y terms.  Take half the linear term, square it, and add it to both sides.  Our linear term is 14.  Half of 14 is 7, and 7 squared is 49. So we add 49 to both sides. y^2+14y+49=2+49, which of course simplifies to y^2+14y+49=51.  The purpose of this is to find the k coodinate of the vertex which will be revealed when we write the perfect square binomial we created during this process: (y+7)^2=51.  Moving the 51 back over by subtraction gives us (y+7)^2-51=x.  The vertex then is (-51,-7).  The formula to find the focus using this vertex is (h+ \frac{1}{4a},k).  As I stated quite a while ago, the leading coefficient on our parabola was a +1 so our "a" value is 1, and the focus is then found in (-51+ \frac{1}{4},-7) which simplifies to (-50.75, -7).  If the vertex is (-51, -7) and the focus is (-50.75, -7), then the distance between them is 1/4, or .25.  That means that the directrix is also .25 units from the vertex, but in the other direction.  Our directrix is a vertical line, and it will have the equaion x = -51.25.  Summing up, your focus is (-50.75, -7) and your directrix is x = -51.25
7 0
3 years ago
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