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3 years ago

I need help with this ?? I don’t get it

Mathematics

1 answer:

Georgia [21]3 years ago

8 0

Sorry I don’t get it either but I had to respond to make a comment to make a question?

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Find the slope of the given equation<br> y=4x-7

san4es73 [151]

$The\ slope-intercept\ form:y=mx+b\\m-the\ slope;\ b-the\ y-intercept\\\\You\ have:y=4x-7\\\\therefore\ \boxed{the\ slope\ =4}$

7 0

3 years ago

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38.07 is 9% of what number?

Nataliya [291]

$38.07 = \frac{9}{100} x$

$38.07 \times \frac{100}{9} = x$

$\frac{3807}{9} = x$

$423 = x$

6 0

3 years ago

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Help me with this please!!

qaws [65]

Answer:

Yes; K= -2 and y=-2x

Step-by-step explanation:

1+2=3

3+2=5

8 0

3 years ago

Write the scale factors and values for x for the pairs of similar triangles below. 9 cm x cm 4 cm 2 cm Scale Scale Factor: X=

Neporo4naja [7]

The scale factor of the similar triangles is: 1/2. The value of x is: 4.5 cm.

<h3>Scale Factor of Similar Triangles</h3>

Scale factor of similar triangles is the ratio of their corresponding sides.

Given the two similar triangles in the diagram attached below, we have the following scale factor as:

Scale factor = 2/4 = 1/2

Therefore:

x = 1/2 × 9

x = 4.5 cm.

Therefore, the scale factor of the similar triangles is: 1/2. The value of x is: 4.5 cm.

Learn more about scale factor on:

brainly.com/question/2826496

8 0

3 years ago

Evaluate the sum of the following finite geometric series.

rjkz [21]

Answer:

$\large\boxed{\dfrac{156}{125}\approx1.2}$

Step-by-step explanation:

<h3>Method 1:</h3>

$\sum\limits_{n=1}^4\left(\dfrac{1}{5}\right)^{n-1}\\\\for\ n=1\\\\\left(\dfrac{1}{5}\right)^{1-1}=\left(\dfrac{1}{5}\right)^0=1\\\\for\ n=2\\\\\left(\dfrac{1}{5}\right)^{2-1}=\left(\dfrac{1}{5}\right)^1=\dfrac{1}{5}\\\\for\ n=3\\\\\left(\dfrac{1}{5}\right)^{3-1}=\left(\dfrac{1}{5}\right)^2=\dfrac{1}{25}\\\\for\ n=4\\\\\left(\dfrac{1}{5}\right)^{4-1}=\left(\dfrac{1}{5}\right)^3=\dfrac{1}{125}$

$\sum\limits_{n=1}^4\left(\dfrac{1}{5}\right)^{n-1}=1+\dfrac{1}{5}+\dfrac{1}{25}+\dfrac{1}{125}=\dfrac{125}{125}+\dfrac{25}{125}+\dfrac{5}{125}+\dfrac{1}{125}=\dfrac{156}{125}$

<h3>Method 2:</h3>

$\sum\limits_{n=1}^4\left(\dfrac{1}{5}\right)^{n-1}\to a_n=\left(\dfrac{1}{5}\right)^{n-1}\\\\\text{The formula of a sum of terms of a geometric series:}\\\\S_n=a_1\cdot\dfrac{1-r^n}{1-r}\\\\r-\text{common ratio}\to r=\dfrac{a_{n+1}}{a_n}\\\\a_{n+1}=\left(\dfrac{1}{5}\right)^{n+1-1}=\left(\dfrac{1}{5}\right)^n\\\\r=\dfrac{\left(\frac{1}{5}\right)^n}{\left(\frac{1}{5}\right)^{n-1}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\r=\left(\dfrac{1}{5}\right)^{n-(n-1)}=\left(\dfrac{1}{5}\right)^{n-n+1}=\left(\dfrac{1}{5}\right)^1=\dfrac{1}{5}$

$a_1=\left(\dfrac{1}{5}\right)^{1-1}=\left(\dfrac{1}{5}\right)^0=1$

$\text{Substitute}\ a_1=1,\ n=4,\ r=\dfrac{1}{5}:\\\\S_4=1\cdot\dfrac{1-\left(\frac{1}{5}\right)^4}{1-\frac{1}{5}}=\dfrac{1-\frac{1}{625}}{\frac{4}{5}}=\dfrac{624}{625}\cdot\dfrac{5}{4}=\dfrac{156}{125}$

5 0

4 years ago