All categories

3 years ago

What is the measure of n? 6 24 n m n = [?]

Mathematics

1 answer:

spin [16.1K]3 years ago

3 0

Answer:

n = 12

Step-by-step explanation:

By applying geometric mean theorem in the given right angle triangle,

$\frac{AD}{BD}=\frac{BD}{DC}$

BD² = AD × DC

Now substitute the values of each side given,

n² = 6 × 24

n² = 144

n = 12

You might be interested in

Pls help answer this

Paladinen [302]

Answer: Third option

Step-by-step explanation:

For this exercise it is important to remember the following:

1. By definition, the Associative property of addition states that it does not matter how you grouped the numbers, you will always obtained the same sum.

2. The rule for the Associative property of addition is the following (given three numbers "a", "b" and "c"):

$a + (b + c) = (a + b) + c$

Knowing the information shown before, you can identify in the picture attached that the option that illustrates the Associative property of addition is the third one. This is:

$(11+8)+1=11+(8+1)$

As you can notice that you will always get the same result:

$(19)+1=11+(9)\\\\20=20$

8 0

3 years ago

QUESTION WORTH 15 POINTS!! FINALS!! NO WRONG ANSWERS PLEASE!!

Xelga [282]

Answer:

Somewhere around 27k

Step-by-step explanation:

4 0

3 years ago

What is the factorization of the trinomial below?x3 - 12x2 + 35x?

Fed [463]

X³ - 12x² + 35x

x(x² - 12x + 35)

x(x-5)(x-7)

4 0

4 years ago

Read 2 more answers

A painter is placing a ladder to reach the third story window, which is 23 feet above the ground and makes an angle with the gro

oksian1 [2.3K]

Answer:

Step-by-step explanation:

4 0

3 years ago

A bicycle lock has a four-digit code. The possible digits, 0 through 9, cannot be repeated. What is the probability that the loc

kozerog [31]

First let's find the number of the elements in the sample space, that is the total number of codes that can be produced.

The first digit is any of {0, 1, 2...,9}, that is 10 possibilities
the second digit is any of the remaining 9, after having picked one.
and so on...

so in total there are 10*9*8*7 = 5040 codes.

a. What is the probability that the lock code will begin with 5?

Lets fix the first number as 5. Then there are 9 possibilities for the second digit, 8 for the third on and 7 for the last digit.

Thus, there are 1*9*8*7=504 codes which start with 5.

so

P(first digit is five)= $\frac{n(first -digit- is- 5)}{n(all-codes)}= \frac{1*9*8*7 }{10*9*8*7 }= \frac{1}{10}=0.1$

b. <span>What is the probability that the lock code will not contain the number 0?

from the set {0, 1, 2...., } we exclude 0, and we are left with {1, 2, ...9}

from which we can form in total 9*8*7*6 codes which do not contain 0.

P(codes without 0)=n(codes without 0)/n(all codes)=(9*8*7*6)/(10*9*8*7)=6/10=0.6

Answer:

0.1 ; 0.6</span>

4 0

3 years ago

Read 2 more answers