The volume of the polyhedron rounded to the nearest tenth is _____

A recipe for a soup.calls for 1/3 cup of chopped onion and 2/6 cup of chopped

Anestetic [448]

Answer: 2/3

Step-by-step explanation:

5 0

3 years ago

Tyler completely filled the Box shown below with unit cubes with no gaps or overlaps even counted the number of Cubes that he us

Mamont248 [21]

Question:

The options are

A. area

B. height

C. volume

D. perimeter

Answer:

The correct option is;

C. volume

Step-by-step explanation:

Here we note that the size of the unit cube is 1 cubic unit

When the box is filled with the unit cubes the total number of unit cubes represent the volume capacity of the box into which the number of nit cubes are placed.

The volume is a quantity that is also represented by the product of the length, width and height dimensions of the cube.

5 0

3 years ago

37. Verify Green's theorem in the plane for f (3x2- 8y2) dx + (4y - 6xy) dy, where C is the boundary of the

Nastasia [14]

I'll only look at (37) here, since

• (38) was addressed in 24438105

• (39) was addressed in 24434477

• (40) and (41) were both addressed in 24434541

In both parts, we're considering the line integral

$\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dy$

and I assume C has a positive orientation in both cases

(a) It looks like the region has the curves y = x and y = x ² as its boundary***, so that the interior of C is the set D given by

$D = \left\{(x,y) \mid 0\le x\le1 \text{ and }x^2\le y\le x\right\}$

• Compute the line integral directly by splitting up C into two component curves,

C₁ : x = t and y = t ² with 0 ≤ t ≤ 1

C₂ : x = 1 - t and y = 1 - t with 0 ≤ t ≤ 1

Then

$\displaystyle \int_C = \int_{C_1} + \int_{C_2} \\\\ = \int_0^1 \left((3t^2-8t^4)+(4t^2-6t^3)(2t))\right)\,\mathrm dt \\+ \int_0^1 \left((-5(1-t)^2)(-1)+(4(1-t)-6(1-t)^2)(-1)\right)\,\mathrm dt \\\\ = \int_0^1 (7-18t+14t^2+8t^3-20t^4)\,\mathrm dt = \boxed{\frac23}$

*** Obviously this interpretation is incorrect if the solution is supposed to be 3/2, so make the appropriate adjustment when you work this out for yourself.

• Compute the same integral using Green's theorem:

$\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dy = \iint_D \frac{\partial(4y-6xy)}{\partial x} - \frac{\partial(3x^2-8y^2)}{\partial y}\,\mathrm dx\,\mathrm dy \\\\ = \int_0^1\int_{x^2}^x 10y\,\mathrm dy\,\mathrm dx = \boxed{\frac23}$

(b) C is the boundary of the region

$D = \left\{(x,y) \mid 0\le x\le 1\text{ and }0\le y\le1-x\right\}$

• Compute the line integral directly, splitting up C into 3 components,

C₁ : x = t and y = 0 with 0 ≤ t ≤ 1

C₂ : x = 1 - t and y = t with 0 ≤ t ≤ 1

C₃ : x = 0 and y = 1 - t with 0 ≤ t ≤ 1

Then

$\displaystyle \int_C = \int_{C_1} + \int_{C_2} + \int_{C_3} \\\\ = \int_0^1 3t^2\,\mathrm dt + \int_0^1 (11t^2+4t-3)\,\mathrm dt + \int_0^1(4t-4)\,\mathrm dt \\\\ = \int_0^1 (14t^2+8t-7)\,\mathrm dt = \boxed{\frac53}$

• Using Green's theorem:

$\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dx = \int_0^1\int_0^{1-x}10y\,\mathrm dy\,\mathrm dx = \boxed{\frac53}$

4 0

3 years ago

I need help simplifying both of these. thank you!

4vir4ik [10]

<h3>Answer:</h3>

-100x +100; 3
5x +81; 162

<h3>Step-by-step explanation:</h3>

The distributive property is your friend. It tells you ...

a(b + c) = ab + ac

It can also be used to simplify the product of binomials (or other polynomials).

(a +b)^2 = (a +b)(a +b) = a(a +b) + b(a +b) = a^2 +ab +ab +b^2

(a +b)^2 = a^2 +2ab + b^2 . . . . . . . worth remembering

1. (x -10)^2 -x(x +80) = (x^2 -20x +100) +(-x^2 -80x)

= -100x +100 . . . . . . simplified form

For the purposes of calculation, it can be easier to factor out 100:

= 100 (1 -x)

Then for x = 0.97

= 100(1 -0.97) = 100(0.03) = 3

___

2. (2x +9)^2 -x(4x +31) = (4x^2 +36x +81) -4x^2 -31x = 5x +81

For x = 16.2, this is ...

5(16.2) +81 = 81 +81 = 162

_____

The purpose of the attachment is to show the evaluation is correct.

5 0

3 years ago

2(10.8 k+ 2.9) What's the answer

motikmotik

21.6k + 11.8

I believe is the answer good luck!

3 0

3 years ago

The volume of the polyhedron rounded to the nearest tenth is ______ cm3.