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Ugo [173]
3 years ago
13

An item is priced at $14.74. If the sales tax is 4%, what does the item cost including sales tax? A. $20.64 B. $15.33 C. $0.59 D

. $30.07
Mathematics
1 answer:
otez555 [7]3 years ago
4 0
The question already has all the information's that are required for getting to the solution. It is important to minutely look at all the details provided.
Actual price of the item = $14.74
Percentage of sales tax that needs to be added = 4%
Then
Amount of sales tax that needs to be added = (4/100) * 14.74 dollars
                                                                       = 58.96/100 dollars
                                                                       = 0.5896 dollars
                                                                       = 0.59 dollars
Then
The cost of the item including sales tax = (14.74 + 0.59) dollars
                                                                 = 15.33 dollars
From the above deduction we can easily conclude that the correct option among all the options given in the question is option "B".
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x^{2}+2x+1=-4+1

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therefore

case a) is not the solution of the problem

<u>case b)</u> x^{2}-2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=-4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=-4+1

x^{2}-2x+1=-3

Rewrite as perfect squares

(x-1)^{2}=-3

(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i

therefore

case b) is not the solution of the problem

<u>case c)</u> x^{2}+2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=4+1

x^{2}+2x+1=5

Rewrite as perfect squares

(x+1)^{2}=5

(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}

therefore

case c) is not the solution of the problem

<u>case d)</u> x^{2}-2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=4+1

x^{2}-2x+1=5

Rewrite as perfect squares

(x-1)^{2}=5

(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}

therefore

case d) is the solution of the problem

therefore

<u>the answer is</u>

x^{2}-2x-4=0

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