All categories

3 years ago

Negative three times a number is at least nine

Mathematics

1 answer:

Nat2105 [25]3 years ago

4 0

Hi Raulrey! -3 x -3 = 9, hope that helps :)

You might be interested in

What is the solution to the equation below? Round your answer to two decimal places? (apex) 5+8*In x=15.8

Sliva [168]

Option A : $x=3.86$ is the solution of the equation.

Explanation:

The equation is $5+8 \ln x=15.8$

To determine the value of x, let us simplify the equation.

Subtracting 5 from both sides of the equation, we have,

$5+\ 8 \ ln \ x-5=15.8-5$

Simplifying, we get,

$8 \ ln \ x= 10.8$

Now , dividing both sides of the equation by 8, we get,

$\ ln \ x=1.35$

Using the logarithmic definition that if $\log _{a}(b)=c$ then $b=a^{c}$

Thus, rewriting the above expression $\ ln \ x=1.35$ using the logarithmic definition, we have,

$\ln \ x =1.35$ ⇒ $x=e^{1.35}$

Substituting the value of $e^{1.35}$=3.85742...$ , we get,

$x=3.85742 \ldots$

Rounding off the answer to two decimal places, we get,

$x=3.86$

Hence, the solution of the equation is $x=3.86$

Therefore, Option A is the correct answer.

8 0

2 years ago

Which graph shows the line y = -3x + 1

Nikolay [14]

Line B

Explanation:

The slope is negative so the line is going to the left. The y-intersect is 1.

7 0

3 years ago

Read 2 more answers

mr kato's closet contains 10 neckties there is ratio of 2 neckties to 3 shirts in the closet how many shirts does mr kato have i

slega [8]

10 divided by 2=5
5 times 3 is 15
15 shirts

8 0

3 years ago

5x - 3y = 24////standard form to slope intercept form

zhenek [66]

Answer:

y =5/3x - 8

Step-by-step explanation:

5x - 3y = 24

-3y = -5x + 24

y = 5/3x - 8

7 0

2 years ago

The vertices of xyz are x (1,-4)

dexar [7]

Answer:

5. The vertices of ΔX'Y'Z' are (-3, -7), (-6, -4), (-1, -2)

6. The vertices of ΔX'Y'Z' are (6, -7), (3, -4), (8, -2)

Step-by-step explanation:

If the point (x, y) translated by T → (h, k), then its image is (x + h, y + k)

In ΔXYZ

∵ X = (1, -4), Y = (-2, -1), Z = (3, 1)

∵ T → (-4, -3)

∴ h = -4 and k = -3

→ Use the rule above to find the image of the vertices of the Δ

∵ X' = (1 + -4, -4 + -3)

∴ X' = (-3, -7)

∵ Y' = (-2 + -4, -1 + -3)

∴ Y' = (-6, -4)

∵ Z' = (3 + -4, 1 + -3)

∴ Z' = (-1, -2)

∴ The vertices of ΔX'Y'Z' are (-3, -7), (-6, -4), (-1, -2)

In ΔXYZ

∵ X = (1, -4), Y = (-2, -1), Z = (3, 1)

∵ T → (5, -3)

∴ h = 5 and k = -3

→ Use the rule above to find the image of the vertices of the Δ

∵ X' = (1 + 5, -4 + -3)

∴ X' = (6, -7)

∵ Y' = (-2 + 5, -1 + -3)

∴ Y' = (3, -4)

∵ Z' = (3 + 5, 1 + -3)

∴ Z' = (8, -2)

∴ The vertices of ΔX'Y'Z' are (6, -7), (3, -4), (8, -2)

6 0

3 years ago