I was thinking that the answer could be
2.810; log3 21.903
OR
<span> 2.810; log3 55.2 </span>
So,<span> log5 of 92 is between 2.5 and 3 Correct answer is A</span>
Answer: 11.25 secs
Step-by-step explanation:
So in this sense the rockets origin or the ground is modeled at h=0 so the time required if used on a table shows that h=0 between the values of 11 and 12. So if you plug and chug decimal values between these two values you get exactly 0 at t=11.25 so it takes approximately 11.25 seconds for the rocket to return to the ground
Answer:
Step-by-step explanation:
(7^0/7^5)^1/5
= (1 / 7^5)^ 1/5
= (7^-5)^1/5
= 7^-1
= 1/7 is the correct answer.
Answer:
B
Step-by-step explanation:
it is an exponential function
