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zaharov [31]
3 years ago
6

The ages of four cousins are consecutive integers. Let the integers equal n, n+1, n+2, n+3. The sum of their ages is 26. How old

is each cousin?
Mathematics
1 answer:
Elena-2011 [213]3 years ago
3 0
The answers would be n=5 n+1=6 n+2=7 n+3=8 because the equation is 4n+6=26. You add all the variables and numbers up to get that equation. Then you subtract 6 from 26 to get 20. Finally you divide 20 by 4 to get n=5. To get all the ages you replace n with 5 and complete the equation. For example n+1 is actually 5+1.
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