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zaharov [31]
3 years ago
6

The ages of four cousins are consecutive integers. Let the integers equal n, n+1, n+2, n+3. The sum of their ages is 26. How old

is each cousin?
Mathematics
1 answer:
Elena-2011 [213]3 years ago
3 0
The answers would be n=5 n+1=6 n+2=7 n+3=8 because the equation is 4n+6=26. You add all the variables and numbers up to get that equation. Then you subtract 6 from 26 to get 20. Finally you divide 20 by 4 to get n=5. To get all the ages you replace n with 5 and complete the equation. For example n+1 is actually 5+1.
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Nathan and his brother Zach love to play video games. Right now, Nathan's score is 11 less than 2 times Zach's score.-example, i
sashaice [31]

Zach's score, Z, and Nathan's score, N, are related by the formula

2Z-11=N.

This is further explained below.

<h3>What are algebraic expressions?</h3>

Generally, Assume Nathan has a score of N and Zach has a score of Z.

Zach's score is 11 points higher than Nathan's.

It implies,

N equals twice of Z minus 11.

We may format it as follows:

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There are now four possible outcomes for these two brothers' scores:

Zach's score will be determined using algebraic formulas if Nathan's score is 81.

2Z - 11 = 81

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Zach's score will be 61 if Nathan receives a score of 111.

Zach's score will be 121 if Nathan's score is 231 or higher.

Zach's score will be 456 if Nathan's score is 901.

The formula 2Z - 11 = Z is a rule that connects Nathan's and Zach's scores.

Visit to learn more about algebraic expressions.

brainly.com/question/953809

#SPJ1

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Write in standard form: 800,000 + 70,000 + 400 + 6
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Step-by-step explanation:

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