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3 years ago

Solve for the inverse g(x) = 2x^2-6/9

1 answer:

4 0

Answer:f(x)=x2−6x−9 f ( x ) = x 2 - 6 x - 9. Replace f(x) f ( x ) with y y . y=x2−6x−9 y = x 2 - 6 x - 9. Interchange the variables. x=y2−6y−9 x = y 2 - 6 y - 9.

Step-by-step explanation:

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If sin Θ = negative square root 3 over 2 and π < Θ < 3 pi over 2, what are the values of cos Θ and tan Θ? cos Θ = negative

andreev551 [17]

Answer:

The correct option is the option with:

cos Θ = 1/2

tan Θ = -√3

Step-by-step explanation:

Given that

sin Θ = -√3/2

We want to find the values of

cos Θ and tan Θ

First of all,

arcsin (-60) = -√3/2

=> Θ = 60

tan Θ = (sin Θ)/(cos Θ)

tan Θ = (-√3/2)/(cos Θ)

cos Θ tan Θ = (1/2)(-√3)

Knowing that Θ = -60,

and cos Θ = cos(-Θ), comparing the last equation, we have

cos Θ = 1/2

tan Θ = -√3

8 0

3 years ago

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If h = 3.5u, what is the value of h when u = 17?<br> Give any decimal answers to 1 d.p.

kirza4 [7]

h=3.5u

Put u=17

h=3.5(17)
h=51+8.5
h=59.5

3 0

2 years ago

Read 2 more answers

A.0.5×10^4

Juliette [100K]

Answer:

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Step-by-step explanation:

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3 years ago

PLS HELP. Find the first four terms of the recursive sequence defined by the following formula:

Gnoma [55]

Answer:

see explanation

Step-by-step explanation:

Given the recursive formula $a_{n}$ = $\frac{a_{n-1} }{4}$ and

$a_{4}$ = 2 $\frac{1}{4}$ = $\frac{9}{4}$ , then

$\frac{a_{3} }{4}$ = $\frac{9}{4}$ ( multiply both sides by 4 )

a₃ = 4 × $\frac{9}{4}$ = 9

$\frac{a_{2} }{4}$ = 9 ( multiply both sides by 4 )

a₂ = 36

$\frac{a_{1} }{4}$ = 36 ( multiply both sides by 4 )

a₁ = 144

The first 4 terms are

144, 36, 9, 2 $\frac{1}{4}$

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3 years ago

I need help for this to pass my last math class please help and show your work

Maksim231197 [3]

-12 + 3x + 2 = 5x - 10 - 8x
-10 + 3x = -3x -10
-10 + 6x = -10
6x = 0
x = 0

3 0

3 years ago

Solve for the inverse g(x) = 2x^2-6/9​

Solve for the inverse g(x) = 2x^2-6/9