Answer:
The probability of getting a mottled offspring is 0%. There is no A2 allele involved in the cross.
Explanation:
<u>Available data</u>:
- The gene for petal color in a flower has incomplete dominance
- Two A1 alleles (A1A1) express black color
- Two A2 alleles (A2A2) express white color
- One of each allele (A1A2) express mottled color
In a cross between two black flowers, there is no allele A2, there are just two alleles A1. So, the cross is:
Parental) A1A1 x A1A1
Gametes) A1 A1 A1 A1
Punnet Square) A1 A1
A1 A1A1 A1A1
A1 A1A1 A1A1
F1 Phenotypes: 100% black flowers
F1 Genotype: 100% A1A1
There are 0% of probabilities of getting a mottled offspring.
Answer:
it wouldn't work
Explanation:
In a heterozygous genotype the dominant allele completely masks the effect of the recessive allele in the organism's phenotype.
Answer:
<em>a cell is a tissue as an atom is to a <u>molecule</u>. </em>
<em>hope</em><em> </em><em>this helps</em><em> </em><em><</em><em>3</em>
