The math club could rent the room for up to 8 hours. I have also attached a picture of the work in case you need it.
A. 3045.9
B. 156.9
C. 29.385
D. 214.5
E. 457.38
F. 4380.4
G. 80096.4
H. 1788
A. 3.3
B. 3.5
C. 15.64
D. 11.52
E. 31.98
F. 376.992
E. 767.208
F. 100.455
Answer:
AC = 127,26 f distance from home plate to second base
Step-by-step explanation:
Let call A , B , C Home plate, first base and second base respectively
These three point form a right triangle with legs ( AB = BC = 90 feet)
we have an isosceles triangle with a right angle and two angles of 45⁰
So we need to compute distance AC (hypotenuse)
AC² = AB² + BC² ⇒ AC² = 2AB² ⇒ AC = AB √2
AC = 90 * 1,414
AC = 127,26 f
The question is not clear.
I will take a guess at what you meant
You have 30 Choc Chip cookies
and 24 sugar cookies..
What is the largest divisor or factor of 30 and 24 have in common?
30 Factors (1,2,3,5,6,10,15,30)
24 Factors (1,2,3,4,6,8,12,24)
6 is the largest factor
So you can create 6 bags:
6 ×5 is 30
6×4 is 24
containing 5 Choc Chip and 4 sugar in each bag.
