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marishachu [46]
3 years ago
14

Determine the y-intercept of the function y=log3(x+81)

Mathematics
1 answer:
zavuch27 [327]3 years ago
5 0
Here u go, i hope this helped

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Find the nth Maclaurin polynomial for the function. f(x) = sec(x), n = 2 P_2(x) =
Alika [10]

Answer:

\mathbf{P_2(x) = 1+\dfrac{x^2}{2}}

Step-by-step explanation:

Given that:

f(x) = sec (x)  , n = 2

Where are to find P_2(x)

Suppose ; f(x) = sec (x)  , n = 2

then

f(0) = sec (0) = 1

f'(x) = sec (x)* tan (x)|_{x=0} = 0

f''(x) = sec (x)*tan ^2(x)+ sec (x) * sec^2(x)

f''(x) = sec (x)*tan ^2(x)|_{x=0} + sec^3(x)

f''(x) = 0 + sec^3(0)

f''(x) = 1

f(x) = f(0) + \dfrac{f'(0)x}{1!}+ \dfrac{f''(0)x^2}{2!}+  \dfrac{f'''(0)x^3}{3!}+...

f(x) = 1 + \dfrac{0}{1!}x+ \dfrac{x^2}{2!}+...

f(x) = 1 + \dfrac{x^2}{2}+...

since order n =2

\mathbf{P_2(x) = 1+\dfrac{x^2}{2}}

8 0
3 years ago
Solve the problems. Write the complete proof in your paper homework and for online (only) complete the probing statement (if any
Luda [366]

Answer:

Hence proved that m∠AOD = m∠BCD.

Step-by-step explanation:

Given:

A Trapezoid with AC and BD as diagonals with O as intersection point to it.

Four angles formed at A and D are equal.

To Prove:

m∠AOD = m∠BCD

Proof:

Consider a Quadrilateral ABCD as trapezoid with diagonals as AC and BD

(Refer the Attachment).

And AB=CD which means the Quadrilateral ABCD isosceles in nature

i.e. angle A=angle D

Now  

Consider triangle AOD and triangle BCD

Apply sum of all angles of triangle is 180.

And also

m∠2+∠AOD+m∠3=180

∠AOD=180-m∠2-m∠3..............equation(1)

And for Triangle BCD

m∠BCD=180-m∠3-m∠4,.....................Equation(2)

∠A=∠D................ as Quadrilateral is  Isosceles.

i.e.∠2=∠3

That means by transitive property,

∠1=∠4=∠3=∠2

Using this values in above equation(1) we get ,

∠AOD=180-∠3-∠4.......................(3)

Now comparing equation 2 and 3 we get

RHS is equal for both equation that means LHS is also equal .

Therefore ∠AOD=∠BCD

Hence proved.

6 0
3 years ago
2. Do the representations below define a function? *
Nat2105 [25]

Answer:

No it is not a function for sure.

5 0
3 years ago
Read 2 more answers
Adding fractions 1/6+2/3=
mars1129 [50]

Answer:

\frac{5}{6}

\frac{1}{6} + \frac{2}{3} is equivalent to \frac{1}{6} + \frac{4}{6}.

This is because \frac{2}{3}=\frac{4}{6}

The rule is, in order to add fractions, your denominators must be equivalent. In other words, you must have the same denominator for both fractions.

<em>Now what do we do? We add!</em>

\frac{1}{6} + \frac{4}{6} =\frac{5}{6}

This is because 4 + 1 = 5.

Your answer is \frac{5}{6}.

I hope this helps!

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>
8 0
3 years ago
Read 2 more answers
Seven times the product of two numbers,a and b,may be written as ?
Softa [21]
It might be 7ab
Hope this helps!
5 0
3 years ago
Read 2 more answers
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