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xenn [34]
3 years ago
8

Solve y2 = 64, where y is a real number. Simplify your answer as much as possible.

Mathematics
1 answer:
Amanda [17]3 years ago
4 0

Answer:

See step by step

Step-by-step explanation:

If you are referring to

y {}^{2}  = 64

Then the answer is 8 or -8,

If you are referring to

y \times 2 = 64

Then answer is 32 or -32 it depends on which one you are referring to.

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The first one

Step-by-step explanation:

They have 2 outputs for the same input

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The sides of a triangle measure 10 feet, 13 feet, and 17 feet.
yuradex [85]
A right triangles hypotenuse is the square root of both of the other side squared. The formula for this is a^2 + b^2= c^2, with c being the longest side. So 10 squared is 100, 13 squared is 169, but. 17 squared is 289. The sum of the other two sides are 269. So it doesn’t equal
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Vondra wants to buy a charm bracelet. Oak Grove Fine Jewelry charges $16 per charm, plus $53 for the bracelet. Sandoval Jewelers
AveGali [126]

Answer:

The bracelet will cost 85$ and it'll have 2 charms.

Step-by-step explanation:

In order to find the total cost of the bracelet and how many charms it'd be we need to build an equation for each store. So we have:

Oak Grove:

total cost = 16*charm + 53

Sandoval:

total cost = 27*charm + 31

We then find the number of charm that'll make them equal, since the price has to be the same on both shops:

16*charm + 53 = 27*charm + 31

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United Flight 15 from New York's JFK airport to San Francisco uses a Boeing 757-200 with 182 seats. Because some people with res
Tcecarenko [31]

Answer:

There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.

Step-by-step explanation:

For each passenger, there are only two outcomes possible. Either they show up for the flight, or they do not show up. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

A probability is said to be unusually low if it is lower than 5%.

For this problem, we have that:

There are 200 reservations, so n = 200.

A passenger consists in a passenger not showing up. There is a .0995 probability that a passenger with a reservation will not show up for the flight. So \pi = 0.0995.

Find the probability that when 200 reservations are accepted for United Flight 15, there are more passengers showing up than there are seats available.

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P(X < 18) = 0.2927.

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What is the sum or difference of 517 37/50 + 312 3/100
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