The measure of angle ABC is 45°
<em><u>Explanation</u></em>
Vertices of the triangle are: A(7, 5), B(4, 2), and C(9, 2)
According to the diagram below....
Length of the side BC (a) 
Length of the side AC (b) 
Length of the side AB (c) 
We need to find ∠ABC or ∠B . So using <u>Cosine rule</u>, we will get...
So, the measure of angle ABC is 45°
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Answer:
Step-by-step explanation:
(40,5) and (0,0) are points on the line.
Slope of line = (40 miles)/(5 minutes) = 8 Mikes per minute
Answer:
Step-by-step explanation:
This first step is to take the square root of the minus which is understood to be - 1
sqrt(-1) = i
So far what you have is
sqrt(-98) = i*sqrt(98)
sqrt(98) is just found the ordinary way
sqrt(98) = sqrt(7*7*2)
sqrt(7*7*2) = 7*sqrt(2)
Answer: 7 * i * sqrt(2) = i7*sqrt(2)
Pick the choice that looks like what you have done for homework.
Answer:
(a - b)^2 = 49 - 4b^2 +2ab
Step-by-step explanation:
Given: a^2 + b^2 = 7b (assuming A is really “a”)
b^2 + (2b - a)^2 = 7^2
Find; (a - b)^2
Plan: Use Algebraic Manipulation
Start with b^2 + (2b - a)^2 = 7^2 =>
b^2 + 4b^2 - 4ab + a^2 = 49 by expanding the binomial.
a^2 + b^2 + 4b^2 - 4ab = 49 rearranging terms
a^2 + b^2 -2ab - 2ab + 4b^2 = 49 =>
a^2 - 2ab + b^2 = 49 - 4b^2 +2ab rearranging and subtracting 4b^2 and adding 2ab to both sides of the equation and by factoring a^2 - 2ab + b^2
(a - b)^2 = 49 - 4b^2 +2ab
Double Check: recalculated ✅ ✅
(a - b)^2 = 49 - 4b^2 +2ab
