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Korolek [52]
3 years ago
13

Please help me. I need help.​

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
5 0

Answer:

the answer should be b but its the answer

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Compare |−49| and |−52|. 50 POINTS HELP ASAP PLEASE ANYONE PLEASE A) |−49| |−52| D) |−49| ≥ |−52|
Georgia [21]

Answer:

|-49| < |-52|

Step-by-step explanation:

|-49| = 49

|-52| = 52

49 < 52

--> |-49| < |-52|

3 0
3 years ago
Read 2 more answers
Raju is cycling at a speed of 30km/h. He applies brakes and stops at a junction in 10s. Calculate the acceleration.
Sedbober [7]

Answer:

Acceleration = 3m/s²

Step-by-step explanation:

Here ,

Initial velocity = 30km/h

Final velocity = 0km/h

Time = 10s

Acceleration = ?

We know ,

A = v-u/t

or , A = 0-30/10

or, A = 30/10

A = 3m/s²

Therefore the acceleration is 3m/s²

7 0
3 years ago
Please help meeeeeee​
otez555 [7]

Answer: its 1/4 per minute i took the test

Step-by-step explanation:

7 0
3 years ago
7)
natulia [17]

Answer:

600 feet

Step-by-step explanation:

3 0
3 years ago
According to a survey, the average American person watches TV for 3 hours per week. To test if the amount of TV in New York City
Neporo4naja [7]

Answer:

Test statistic (t-value) of this one-mean hypothesis test is -2.422.

Step-by-step explanation:

We are given that according to a survey, the average American person watches TV for 3 hours per week. She surveys 19 New Yorkers randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 2.5 hours per week, and the sample standard deviation (s) is 0.9 hours.

We have to test if the amount of TV in New York City is less than the national average.

Let Null Hypothesis, H_0 : \mu \leq 3  {means that the amount of TV in New York City is less than the national average}

Alternate Hypothesis, H_1 : \mu > 3   {means that the amount of TV in New York City is more than the national average}

The test statistics that will be used here is One-sample t-test statistics;

        T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean time = 2.5 hours per week

             s = sample standard deviation = 0.09 hours

             n = sample size = 19

So, <u>test statistics</u> = \frac{2.5 - 3}{\frac{0.9}{\sqrt{19} } } ~ t_1_8

                              = -2.422

Therefore, the test statistic (t-value) of this one-mean hypothesis test (with σ unknown) is -2.422.

8 0
3 years ago
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