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torisob [31]
3 years ago
10

The hexagon GIKMPR and triangle FJN are regular. the dashed line segments form 30 degrees angles.

Mathematics
2 answers:
babunello [35]3 years ago
8 0
Comment
When you go through 180 degrees, what happens is that you follow a straight line until you hit something on the other side of the line.

For example 

A ___________∨____________B

If you start at A and go through ∨ and onward to B, you have effectively gone through a rotation of 180o. 

Just to nail it down, in a rotation through 90° you would travel through a right angle like this one. ⊥ You would start on one of the horizontal ends and when you hit the vertical line you would go up 90° from where you started. If you go clockwise, N would be where R is for 90°.

Answer
You don't want 90 you want 180. I've just done that to explain it a little better.

NO would become OH <<<<<< answer. 


GrogVix [38]3 years ago
7 0

Solution:

As ON is a line segment , and ∠ ON P = 90°= ∠ON M

There are two cases

1. When line segment ON is rotated in clockwise direction by an angle 180°.

  When ON rotated by an angle of 90° in clockwise Direction it reaches OR and then again by 90° take it to OH.

2.  When line segment ON is rotated in anticlockwise direction by an angle 180°.

  When ON rotated by an angle of 90° in Anticlockwise Direction it reaches OK and then again by 90° take it to OH.

So in both the cases segment ON becomes OH i.e N →H.


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<h3>Given:</h3><h3>Large cone:</h3>
  • r= 8 cm
  • h= 20 cm
<h3>Small cone:</h3>
  • r= 4 cm
  • h= 10cm
<h3>Note that:</h3>
  • r: radius
  • h: height
<h3>To find:</h3>
  • The volume of the frustum of the given cone.
<h3>Solution:</h3>
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\large\boxed{Formula: V= \frac{1}{3}\pi{r}^{2}h}

Let's solve!

First, let's find the volume of the smaller cone.

Substitute the values according to the

formula.

V= \frac{1}{3}×\pi×{4}^{2}×10

V= 167.5516082 \: {cm}^{3}

Now, we can round off to the nearest hundredth.

The value in the thousandths place is smaller than 5 so we won't have to round up.

\boxed{V= 167.55 \: {cm}^{3}}

Next, let's find the volume of the bigger cone.

Substitute the values according to the formula.

V= \frac{1}{3}×\pi×{8}^{2}×20

V= 1340.412866 \: {cm}^{3}

Now, we can round off to the nearest hundredth.

The value in thousandths place is smaller than 5 so we won't have to round up.

\boxed{V=1340.41 \: {cm}^{3}}

Now, we can find the volume of the frustum.

We'll have to minus the volume of the smaller cone from the bigger cone.

V= 1340.41-167.55

\large\boxed{V= 1172.86 \: {cm}^{3}}

<u>Hence, the volume of the frustum is 1172.86 cubic centimeters.</u>



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