Five half-full classes + three 3/4 full classes + 2 1/8 empty (which is 7/8 full) classes altogether give us 10 classes without 70 students. Let's assume that one class is x, so we can write it as:
5 * 1/2x + 3 * 3/4x + 2 * 7/8x = 10x - 70
After multiplying and changing it to decimals:
2,5x + 2,25x + 1,75x = 10x - 70
6,5x = 10x - 70 / - 6,5x (both sides)
0 = 3,5x - 70 / + 70 (both sides)
70 = 3,5x / :3,5 (both sides)
x = 20
Check:
5 * 1/2 * 20 + 3 * 3/4 * 20 + 2 * 7/8 * 20 = 10 * 20 - 70
5 * 10 + 3 * 15 + 2 * 17,5 = 200 - 70
50 + 45 + 35 = 130
130 = 130
Correct - there are 20 students in each class (200 students overall)
Answer: There are 200 students in the school when no students are absent.
<A + <C = 180
2x - 7 + x + 4 = 180
3x - 3 = 180
3x = 183
x = 61
<B = 2x + 3 = 2(61) + 3 = 125
Answer
<B = 125°
Answer:
Two
Step-by-step explanation:
Answer:
-573q+74
Step-by-step explanation:
8(10-69q)+3(-7q-2)
80--552q-21q-6
80-573q-6
-573q+74
First you have to have the absolute value isolated so the 2 has to be divided. Then set up the two cases and solve.
