F(g(2)) = 3(x^3 + 1)^2 - 7 = 3(x^6 + 2x^3 + 1) - 7 = 3x^6 + 6x^3 + 3 - 7 = 3x^6 + 6x^3 - 4
I got 54.90196 for that problem
His school, but who is he?
X is 9 Y is 3 and Z is 12
D. x > 5
Combine like terms. 3x - x = 2x and 3 - 7 = -4. The equation is now 2x - 4 > 6. Now add 4 to both sides. 2x > 10. Now divide by 2 to get 'x' alone, leaving you with x > 5
