Answer:
Let X be the number of customer purchased coffee
Let Y be the number of customer purchased donuts
Then
is the number of customer purchased both coffee and donuts
is the number of customer purchased both coffee or donuts
<em><u>The Number of customers purchased only Coffee:</u></em>
Number of customers purchased only donuts =n(X -Y)

n(X-Y) = 59 -16
n(Y - X) = 43
<em><u>The Number of customers purchased only donuts:</u></em>
Number of customers purchased only donuts =n(Y -X)

n(Y - X) = 39 -16
n(Y - X) = 23
<u>The Number of customers did not purchase either of these items:</u>
Number of customers did not purchase either of these items = 
First lets find 



=
= 28
I believe the Answer is A
Answer:
Simply subtract the fail rate from 100; the resulting number is the pass rate. So, if you know that 6 percent of students failed, you would subtract: 100 - 6 = 94 percent is the pass rate for the test.
Step-by-step explanation:
Answer:
2/4 or 1/2
Step-by-step explanation:
Answer:
7
Step-by-step explanation: