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PtichkaEL [24]
2 years ago
10

In a particular lottery, 5 winning numbers are drawn from a set of 37 numbers. What is the probability of picking exactly 2 of t

he winning numbers in this lottery? Round your answer to the nearest
thousandth (three decimal places).
Mathematics
1 answer:
anygoal [31]2 years ago
8 0

Since 5 winning numbers are draw and there are exactly 2 winning numbers, the other 3 numbers chosen have to be incorrect.

The 2 numbers picked right, there are 5C2=10 different possibilities.

The other 3 numbers are just picked from the rest of the 32 numbers. Getting there are 32C3=4960 different possibilities.

For each set of 2 correct winning numbers, you could have the 4960 different losing numbers to match up to make a unique set. This meant that there are 4690*10=46900 different total possibilities.

Now the total different outcomes of how you can choose the numbers are 37C5=435897 outcomes.

Now the way to find probabilities is want/total

The want is 46900 and the total is 435897

Doing the division you get the number rounded to the nearest thousandths as   0.107 or in percent form as

10.759% chance of picking exactly 2 winning numbers.

This seems like a competition problem of some sort therefore I assume that you already know what combinations in form nCk and permutation in form nPk means.

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Answer:

A

Step-by-step explanation:

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krek1111 [17]

Answer:

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Step-by-step explanation:

               3x - 9

              |----------------------------------------

(x +4)       | (3x^2 + 3x - 42 )

                 3x^2 + 12x

           ------------------------------

                          -9x - 42

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-----------------------------------

                                 - 6

Answer: 3x - 9 - (6 / (x+4))

8 0
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6    3
    ------
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3 years ago
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