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faltersainse [42]
3 years ago
14

Let f(x)=x^2-2x-4

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
4 0
F(-1)=1-2=-1
f(4)=16-8-4=4
A(x)=f(4)-f(-1)/4-(-1)
A(x)=4-1/4+1=3/5
You might be interested in
6,666,666×666,666 /1+2+3+4+5+6+5+4+3+2+1 − 777,777×777,777/1+2+3+4+5+6+7+6+5+4+3+2+1
jeka57 [31]

Answer:

111111 \times 1111110 is the simple expression.

Step-by-step explanation:

The expression to be solved:

\dfrac{6,666,666\times666,666 }{1+2+3+4+5+6+5+4+3+2+1} - \dfrac{777,777\times777,777}{1+2+3+4+5+6+7+6+5+4+3+2+1}

First of all, let us solve the first term:

\dfrac{6,666,666\times666,666 }{1+2+3+4+5+6+5+4+3+2+1}\\\Rightarrow \dfrac{6666666\times666666 }{36}\\\Rightarrow \dfrac{6666666\times666666 }{6\times 6}\\\Rightarrow 1111111\times 111111

Now, the right term:

\dfrac{777777\times777777}{1+2+3+4+5+6+7+6+5+4+3+2+1}\\\Rightarrow \dfrac{777777\times777777}{49}\\\Rightarrow \dfrac{777777\times777777}{7 \times 7}\\\Rightarrow 111111 \times 111111

So, the expression to be solved becomes:

1111111\times 111111-111111\times 111111\\\Rightarrow 111111(1111111-1)\\\Rightarrow 111111\times 1111110

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3 years ago
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Vitek1552 [10]

Answer:

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Answer:

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Step-by-step explanation:

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2 years ago
Andrea is told that the means of two groups in a study were statistically significant. She knows the means and standard deviatio
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Answer:

Cohen's D

Step-by-step explanation:

Cohen's D is a statistic that measures effect size. It shows standardised difference between 2 means.

Effect size is defined as how large the effect of a something is or its magnitude.

Cohen's D works effectively when the sample is >50 (that is for large samples). However a correction factor can be used to make results from small samples more accurate

The formular for Cohen's D is:

D = (mean1 - mean2) ÷ (√({standard deviation1}^2 + {standard deviation 2}^2)/2)

This is the most appropriate method in the given scenario

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sladkih [1.3K]

Increases proportionally. (C)

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