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MrMuchimi
2 years ago
5

Find the area of a regular hexagon inscribed in a circle with a radius of 6 feet. Round to the nearest tenth.

Mathematics
1 answer:
raketka [301]2 years ago
7 0

Answer:

93.5ft

Step-by-step explanation:

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Simplify<br>-6√20+2√45+7√5 <br><br>show Woking out to prove ans please​
Dmitry_Shevchenko [17]

Answer:

\sqrt{5}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplifying the radicals

\sqrt{20} = \sqrt{4(5)} = \sqrt{4} × \sqrt{5} = 2\sqrt{5}

\sqrt{45} = \sqrt{9(5)} = \sqrt{9} × \sqrt{5} = 3\sqrt{5}

Thus

- 6(2\sqrt{5}) + 2(3\sqrt{5}) + 7\sqrt{5}

= - 12\sqrt{5} + 6\sqrt{5} + 7\sqrt{5}

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2 years ago
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Answer:

y - 1 = -4(x - 4)

Step-by-step explanation:

The point-slope form looks like y-k = m(x-h), where (h,k) is a point on the line and m is the slope.

Here,  y - 1 = -4(x - 4).  This is in point-slope form.

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3 years ago
Jessie had a piece of cardboard that is 8.5 inches by 11 inches. She makes a picture frame with the cardboard box by cutting out
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16. What are the values of a and b?
MrMuchimi

Answer:

  a = 20; b = 2√101

Step-by-step explanation:

The triangle at upper left and the one at lower right are similar. Ratios of corresponding sides are equal, so ...

  200/a = a/2

  400 = a^2

  √400 = 20 = a

Then, by the Pythagorean theorem, the value of b can be found:

  b = √(a^2 + 2^2) = √(400 +4) = √4·√101

  b = 2√101

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2 years ago
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