Find the area of a regular hexagon inscribed in a circle with a radius of 6 feet. Round to the nearest tenth.
1 answer:
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Answer:
Step-by-step explanation:
A line is perpendicular to another if its slope is the negative reciprocal of the other.
Your lines are in slope intercept form here, y=mx+b, where m is the slope. We can see the given line has slope . The negative reciprocal of that is
, which is the slope of the third answer choice.
Answer: y = 2x + 6
Step-by-step explanation:
Here the equation of line,
y = 2x + 1
y-intercept of the line is, (0, 1)
And, the slope of the line is 2.
Since, If a point (x,y) is dilated by a scale factor k about a point (a,b),
Then transformed point are get by,
Thus, The transformed point of point (0,1) when dilation is occur by the scale factor 2 about the point (0,-4),
Thus, the point of the new line is (0,6)
And, the slope of the new line is 2 ( because in the dilation, the slope of the line does not change)
Thus, the equation of new line,
(y - 6) = 2 (x - 0)
y - 6 = 2x
y = 2x + 6
see the attached figure to better understand the problem
we know that
The Area of the composite figure is equal to the sum of Area 1, Area 2 and Area 3
The Area 1 is a triangle
The Area 2 is a rectangle
The Area 3 is equal a semicircle
therefore
<u>the answer is the option</u>
a triangle, a rectangle, and a semicircle
