All categories

3 years ago

Help me please please please!

Mathematics

1 answer:

Tasya [4]3 years ago

3 0

The answer is D. 5^(-5/6)

You might be interested in

IM2: 4.2.3, 4-86 d Solve for X

krek1111 [17]

Answer:

s v [tw9rg

Step-by-step dpc fbsz

6 0

3 years ago

If (2i/2+i)-(3i/3+i)=a+bi, then a= A. 1/10 B. -10 C. 1/50 D. -1/10

Verizon [17]

Answer:

Option A is correct.

Step-by-step explanation:

We are given:

$\frac{2i}{2+i}-\frac{3i}{3+i} = a+bi$

We need to find the value of a.

The LCM of (2+i) and (3+i) is (2+i)(3+i)

$=\frac{2i(3+i)}{(2+i)(3+i)}-\frac{3i(2+i)}{(2+i)(3+i)}\\=\frac{6i+2i^2}{(2+i)(3+i)}-\frac{6i+3i^2}{(2+i)(3+i)}\\=\frac{6i+2i^2-(6i+3i^2)}{(2+i)(3+i)}\\=\frac{6i+2i^2-6i-3i^2)}{5+5i}\\=\frac{-i^2}{5+5i}\\i^2=-1\\=\frac{-(-1)}{5+5i}\\=\frac{1}{5+5i}$

Now rationalize the denominator by multiplying by 5-5i/5-5i

$=\frac{1}{5+5i}*\frac{5-5i}{5-5i} \\=\frac{5-5i}{(5+5i)(5-5i)}\\=\frac{5-5i}{(5+5i)(5-5i)}\\(a+b)(a-b)= a^2-b^2\\=\frac{5(1-i)}{(5)^2-(5i)^2}\\=\frac{5(1-i)}{25+25}\\=\frac{5(1-i)}{50}\\=\frac{1-i}{10}\\=\frac{1}{10}-\frac{i}{10}$

We are given

$\frac{2i}{2+i}-\frac{3i}{3+i} = a+bi$

Now after solving we have:

$\frac{1}{10}-\frac{i}{10}=a+bi$

So value of a = 1/10 and value of b = -1/10

So, Option A is correct.

8 0

4 years ago

Three tennis balls are packaged in a box as shown below. The box is 12.1 centimeters long, 3.5 centimeters wide, and 3.5 centime

grin007 [14]

The volume is 91.8cm³

7 0

3 years ago

Help please I’m trying to do my homework and don’t understand

11Alexandr11 [23.1K]

Answer:

Answer is 9.

I think this is helpful. Vote it and like me

6 0

3 years ago

I need help with all the ones that don't have answers.

zlopas [31]

- What two consecutive odd integers have a sum of 48?

23 + 25 = 48

- Two negative consecutive integers have a sum of -45. What are the integers?

-22 + -23

- The sum of two consecutive integers 75. What are the two integers?

37 + 38 = 75

- What three consecutive odd integers have a sum of 81?

25 + 27 + 29 = 81

Hope I could help! Have a good one. I believe that is all of the unanswered questions. If I missed one, let me know!

7 0

3 years ago