A set of values A can have a relation with another set B as long as at least one element of A has at least one image in B. Functions are special relations where each element of A (the domain of the function) has one and only one image on B (the range of the function).

By looking at the options, we can see that x=9, x=-8, and x=-1 already have defined values in Y, so if we define another value for any of them the relation will stop being a function. The only possible choice to preserve the function is the option

$\boxed{A)\ (-5,7)}$

8 0

4 years ago

2/9/10 + 1/10 what is the answer

rosijanka [135]

Answer:

The answer is 0.12

7 0

4 years ago

Find a:c and a:b:c of a:b =4:5, b:c=3;5 pls ans with explanation

Lynna [10]

Here's the solution,

a : b = 4 : 5

b : c = 3 : 5

now, we can combine the ratios if the value of b is equal in both of them, and we have to make sure it's the minimum value since we have to obtain it in the simplest form, so let's take the L.C.M of b in both proportions .

L.C.M of b in both ratios is 15

ratio 1.)

a : b = 4 : 5
a : b = 12 : 15

( just multiplied both numbers by 3 to make b = 15 )

ratio 2.)

b : c = 3 : 5
b : c = 15 : 25

( just multiplied both numbers by 5 to make b = 15)

now, simply combine the equations to get,

a : b : c = 12 : 15 : 25

and hence,

a : c = 12 : 25

4 0

3 years ago

lara [203]

The answer you're looking for is D:-0.9, 0.09, 1/11, 1/10

:P

4 0

3 years ago