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liubo4ka [24]
3 years ago
5

Answer now pls I’ll give you brainliest just pls answer

Mathematics
2 answers:
storchak [24]3 years ago
8 0

Answer:

18.)   7,459.82 rounded to the nearest whole number is <u>7,460.</u>

19.)   523.791 rounded to the nearest tenth is<u> 523.8.</u>

20.)   6,507.125 rounded to the nearest hundredth is <u>6,507.13.</u>

hjlf3 years ago
5 0

Answer:

7,460 (or 7460 as some non-native English speakers would write it) since you always round a number down when it ends in 1 through 4, and always round it up when it ends in 5 through 9.

Step-by-step explanation:

pls give me brainliest plssssssssssssssssssssss.

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∆ABC is similar to ∆DEF. The ratio of the perimeter of ∆ABC to the perimeter of ∆DEF is 1 : 10. The longest side of ∆DEF measure
exis [7]

Answer:

Part 1) The length of the longest side of ∆ABC  is 4 units

Part 2) The ratio of the area of ∆ABC to the area of ∆DEF is \frac{1}{100}

Step-by-step explanation:

Part 1) Find the length of the longest side of ∆ABC

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

The ratio of its perimeters is equal to the scale factor

Let

z ----> the scale factor

x ----> the length of the longest side of ∆ABC

y ----> the length of the longest side of ∆DEF

so

z=\frac{x}{y}

we have

z=\frac{1}{10}

y=40\ units

substitute

\frac{1}{10}=\frac{x}{40}

solve for x

x=(40)\frac{1}{10}

x=4\ units

therefore

The length of the longest side of ∆ABC  is 4 units

Part 2) Find the ratio of the area of ∆ABC to the area of ∆DEF

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> the area of ∆ABC

y ----> the area of ∆DEF

z^{2}=\frac{x}{y}

we have

z=\frac{1}{10}

so

z^2=(\frac{1}{10})^2

z^2=\frac{1}{100}

therefore

The ratio of the area of ∆ABC to the area of ∆DEF is \frac{1}{100}

3 0
3 years ago
According to the American Lung Association, 7% of the population has lung disease. Of those having lung disease, 90% are smokers
postnew [5]

Answer:

Probability that a smoker has lung disease = 0.2132

Step-by-step explanation:

Let L = event that % of population having lung disease, P(L) = 0.07

So,% of population not having lung disease, P(L') = 1 - P(L) = 1 - 0.07 = 0.93

S = event that person is smoker

% of population that are smokers given they are having lung disease, P(S/L) = 0.90

% of population that are smokers given they are not having lung disease, P(S/L') = 0.25

We know that, conditional probability formula is given by;

                        P(S/L) = \frac{P(S\bigcap L)}{P(L)}  

                        P(S\bigcap L) = P(S/L) * P(L)

                                      = 0.90 * 0.07 = 0.063

So,  P(S\bigcap L) = 0.063 .

Now, probability that a smoker has lung disease is given by = P(L/S)

      P(L/S) = \frac{P(S\bigcap L)}{P(S)}

P(S) = P(S/L) * P(L) + P(S/L') * P(L')

       = 0.90 * 0.07 + 0.25 * 0.93 = 0.2955

Therefore, P(L/S) = \frac{0.063}{0.2955} = 0.2132

Hence, probability that a smoker has lung disease is 0.2132 .

7 0
4 years ago
Write down in terms of n, an expression for the nth term of the following sequences: 1,8,15,22,29
Crank

Step-by-step explanation:

t1 = 1 = 7*1 - 6

t2 = 8 = 7* 2 - 6

t3 = 15 = 7 * 3 - 6

t4 = 22 = 7 *4 - 6

t5 = 29 = 7 * 5 - 6

-------------------------

Tn = 7n - 6

6 0
3 years ago
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Here Is A Dividend That Might Help Is 12÷6=2
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The Yoga class you wish to take is offering two price quotes: $108 for 5 weeks as (15 classes) or $125 for 8 weeks (24 classes).
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3 years ago
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