Answer:
Surface Area =
inches²
<u><em>OR</em></u>
Surface Area ≈ 24.4 inches²
Step-by-step explanation:
Surface Area = ![a^2+2a\sqrt{\frac{a^2}{4} +h^2}](https://tex.z-dn.net/?f=a%5E2%2B2a%5Csqrt%7B%5Cfrac%7Ba%5E2%7D%7B4%7D%20%2Bh%5E2%7D)
Where a = 2 inches and h = 5 inches
Surface Area = ![(2)^2+2(2)\sqrt{\frac{2^2}{4} + (5)^2}](https://tex.z-dn.net/?f=%282%29%5E2%2B2%282%29%5Csqrt%7B%5Cfrac%7B2%5E2%7D%7B4%7D%20%2B%20%285%29%5E2%7D)
Surface Area = ![4+4\sqrt{\frac{4}{4} +25}](https://tex.z-dn.net/?f=4%2B4%5Csqrt%7B%5Cfrac%7B4%7D%7B4%7D%20%2B25%7D)
Surface Area =
inches²
<u><em>OR</em></u>
Surface Area ≈ 24.4 inches²
Answer:
- 48 oz of 90% (B)
- 72 oz of 65% (A)
Step-by-step explanation:
The amount of salt in the mixture is the sum of the amounts of salt in the constituents. Those amounts are found by multiplying the quantity of solution by the percentage that is salt.
__
Let x represent the quantity of 90% salt solution B, in ounces. Then the number of ounces of salt in the mix is ...
0.90x +0.65(120 -x) = 0.75(120)
0.25x = 0.10(120) . . . . . . subtract 0.65(120) and simplify
x = 48 . . . . . . . . . . . . . divide by 0.25
120 -x = 72 . . . . . . . amount of 65% solution A
She should use 48 ounces of 90% solution B, and 72 ounces of 65% solution A.
Answer with explanation:
It has been asked that ,number of apples which can fit into (60)³ foot Box.
→ Box is in the shape of Cube, having each side equal to 60 foot.
Each side of cube is equal.
Volume of cubical box =Side × Side × Side
=60 × 60 × 60
=216,000 foot³
As volume of an apple is not given.So, we can't say precisely how many apples will fit into the box.
Number of Apples
![=\frac{\text{Volume of box}}{\text{volume of an apple}}\\\\=\frac{216,000}{\text{volume of an apple}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Ctext%7BVolume%20of%20box%7D%7D%7B%5Ctext%7Bvolume%20of%20an%20apple%7D%7D%5C%5C%5C%5C%3D%5Cfrac%7B216%2C000%7D%7B%5Ctext%7Bvolume%20of%20an%20apple%7D%7D)
The equation for this is 2 + n/5 = 10, where n is the number
Answer:
![\boxed{12u^3+8u^2-6u+9}](https://tex.z-dn.net/?f=%5Cboxed%7B12u%5E3%2B8u%5E2-6u%2B9%7D)
Step-by-step explanation:
![(8u^3+8u^2+6)+(4u^3-6u+3) = 8u^3+8u^2+6+4u^3-6u+3](https://tex.z-dn.net/?f=%288u%5E3%2B8u%5E2%2B6%29%2B%284u%5E3-6u%2B3%29%20%3D%208u%5E3%2B8u%5E2%2B6%2B4u%5E3-6u%2B3)
Once
![8x+4x = 12x, \text{ as } x = u^3](https://tex.z-dn.net/?f=8x%2B4x%20%3D%2012x%2C%20%5Ctext%7B%20as%20%7D%20x%20%3D%20u%5E3)
![8u^3+8u^2+6+4u^3-6u+3 = 12u^3+8u^2+6-6u+3 = \boxed{12u^3+8u^2-6u+9}](https://tex.z-dn.net/?f=8u%5E3%2B8u%5E2%2B6%2B4u%5E3-6u%2B3%20%3D%2012u%5E3%2B8u%5E2%2B6-6u%2B3%20%3D%20%5Cboxed%7B12u%5E3%2B8u%5E2-6u%2B9%7D)
You don't need to factor.