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3 years ago

Pls help me complete this

Mathematics

2 answers:

Mama L [17]3 years ago

8 0

Answer:

For the first, top one, it is <u>Outcome</u>

For the second one, it is <u>Event</u>

For the third one, it is <u>Trial</u>

For the fourth one, it is <u>Experimental Probability</u>

For the fifth one, it is <u>Probability</u>

s2008m [1.1K]3 years ago

7 0

Answer:

wow thats alot of "stuff"

Step-by-step explanation:

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Find all solutions <br> 36x²+12x=0

FromTheMoon [43]

Answer:

x = -1/3 or 0

Step-by-step explanation:

Given equation:

$36x^{2} + 12x = 0$

We can factor 12x on the L.H.S since 12x is divisible by 36x² and 12x.

$\implies 36x^{2} + 12x = 0$

$\implies 12x(3x + 1) = 0$

This can lead to two solutions. I have listed them below!

<h2>Solution 1:</h2>

Divide 12x on both sides to open the parentheses.

$\implies 12x(3x + 1) = 0$

$\implies \dfrac{12x(3x + 1)}{12} = \dfrac{0}{12}$

<em>Note: zero divided by any non-zero number is 0.</em>

$\implies \dfrac{12x(3x + 1)}{12} = \dfrac{0}{12}$

$\implies 3x + 1 = 0$

Isolate 3x on one side of the equation.

$\implies 3x + 1 = 0$

$\implies 3x = 0 - 1$

$\implies 3x = -1$

Divide 3 both sides to determine the value of x.

$\implies 3x = -1$

$\implies \dfrac{3x}{3} = \dfrac{-1}{3}$

$\implies \boxed{x = \dfrac{-1}{3}}$

<h2>Solution 2:</h2>

Divide (3x + 1) on both sides to isolate 12x.

$\implies 12x(3x + 1) = 0$

$\implies \dfrac{12x(3x + 1)}{(3x + 1)} = \dfrac{0}{(3x + 1)}$

<em>Note: zero divided by any non-zero number is 0.</em>

$\implies \dfrac{12x(3x + 1)}{(3x + 1)} = \dfrac{0}{(3x + 1)}$

$\implies 12x = 0$

Divide 12 both sides to determine the value of x.

$\implies 12x = 0$

$\implies \dfrac{12x}{12} = \dfrac{0}{12}$

$\implies \boxed{x = 0}$

Therefore, the solutions for x are -1/3 or 0.

Learn more about this topic: brainly.com/question/295675

5 0

2 years ago

Read 2 more answers

Consider the curve of the form y(t) = ksin(bt2) . (a) Given that the first critical point of y(t) for positive t occurs at t = 1

mafiozo [28]

Answer:

(a). y'(1)=0 and y'(2) = 3

(b). $y'(t)=kb2t\cos(bt^2)$

(c). $b = \frac{\pi}{2} \text{ and}\ k = \frac{3}{2\pi}$

Step-by-step explanation:

(a). Let the curve is,

$y(t)=k \sin (bt^2)$

So the stationary point or the critical point of the differential function of a single real variable , f(x) is the value $x_{0}$ which lies in the domain of f where the derivative is 0.

Therefore, y'(1)=0

Also given that the derivative of the function y(t) is 3 at t = 2.

Therefore, y'(2) = 3.

(b).

Given function, $y(t)=k \sin (bt^2)$

Differentiating the above equation with respect to x, we get

$y'(t)=\frac{d}{dt}[k \sin (bt^2)]\\ y'(t)=k\frac{d}{dt}[\sin (bt^2)]$

Applying chain rule,

$y'(t)=k \cos (bt^2)(\frac{d}{dt}[bt^2])\\ y'(t)=k\cos(bt^2)(b2t)\\ y'(t)= kb2t\cos(bt^2)$

(c).

Finding the exact values of k and b.

As per the above parts in (a) and (b), the initial conditions are

y'(1) = 0 and y'(2) = 3

And the equations were

$y(t)=k \sin (bt^2)$

$y'(t)=kb2t\cos (bt^2)$

Now putting the initial conditions in the equation y'(1)=0

$kb2(1)\cos(b(1)^2)=0$

2kbcos(b) = 0

cos b = 0 (Since, k and b cannot be zero)

$b=\frac{\pi}{2}$

And

y'(2) = 3

$\therefore kb2(2)\cos [b(2)^2]=3$

$4kb\cos (4b)=3$

$4k(\frac{\pi}{2})\cos(\frac{4 \pi}{2})=3$

$2k\pi\cos 2 \pi=3$

$2k\pi(1) = 3$$

$k=\frac{3}{2\pi}$

$\therefore b = \frac{\pi}{2} \text{ and}\ k = \frac{3}{2\pi}$

7 0

4 years ago

A test subject is randomly selected for a pregnancy test. What is the probability of getting a subject who is not pregnant, give

Scilla [17]

First we need to choose from "Posivite Test" column:
$\frac{12}{12+78} = \frac{12}{90} = 0,1333(3)$

3 0

4 years ago

Read 2 more answers

A garden has an area of 240 ft. Its length is 8 ft more than its width. What are the dimensions of the

solong [7]

Answer:

w=12

l=20

Step-by-step explanation:

The area can be found using the following equation:

$A=lw$

Given the information provided, we are also told the following:

$l=w+8$

Therefore, we can plug in our length and our area:

$240=w(w+8)\\240=w^2+8w\\\\w^2+8w-240=0$

We can solve by using the quadratic formula.

$w=\frac{-8+\sqrt{8^2-4(1)(-240)} }{2(1)}=12 \\\\$

w=12, so w+8=20.

7 0

3 years ago

Read 2 more answers

A company sells a chair for $450. It costs them $350 to make each chair, plus fixed costs for operation of $20,000

lianna [129]

The cost and revenue function of the company are as follows;

cost function = 350x + 20000

revenue function = 100x - 20000

<h3>How to find the cost and revenue function?</h3>

It costs them $350 to make each chair, plus fixed costs for operation of $20,000. Therefore,

let

x = number of chair

cost function = 350x + 20000

The company sells a chair for $450. Therefore,

revenue function = 450x - (350x + 20000)

revenue function = 450x - 350x - 20000

revenue function = 100x - 20000

learn more on cost and revenue here: brainly.com/question/14097232

#SPJ1

6 0

2 years ago