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qaws [65]
3 years ago
5

< Nearpod: Make X c 1) 2x – 5 = 19

Mathematics
1 answer:
Neko [114]3 years ago
6 0

Answer:

x=12

Hope This Helps

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Answer:

Step-by-step explanation:

Indicates leg lengths of 1 and√3 and hypotenuse 2, the desired ratio is √3/2

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3 years ago
You are asked to find the space occupied by the shape below. Will you calculate its area or volume? A cube shape. area volume
Debora [2.8K]

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volume

Step-by-step explanation:

the amount of space enclosed by an object or shape, how much 3-dimensional space

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3 years ago
My brainly username is kinda hot
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Answer: Lol, it just says “Invisible”, but ngl it is pretty cool

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3 years ago
A standard number cube has 6 sides labeled 1 to 6. apu rolls a standard number cube 30 times. How many times can
Leviafan [203]

Answer:

The expected value of rolling a 5 or 6 is 10.

Step-by-step explanation:

The sample space of rolling a standard number cube is:

S = {1, 2, 3, 4, 5 and 6}

The cube is standard, this implies that each side has an equal probability of landing face-up.

So, the probability of all the six outcomes is same, i.e. \frac{1}{6}.

Now it is provided that Apu rolls the cube <em>n</em> = 30 times.

Let the random variable <em>X</em> represent the value on the face of cube.

The event of rolling a 5 and rolling a 6 are mutually exclusive, i.e. they cannot occur together.

So, P (X = 5 and X = 6) = 0.

Compute the probability of getting a 5 or 6 as follows:

P (X = 5 or X = 6) = P (X = 5) + P (X = 6) - P (X = 5 and X = 6)

                            = P (X = 5) + P (X = 6)

                            =\frac{1}{6}+\frac{1}{6}\\\\=\frac{2}{6}\\\\=\frac{1}{3}

Compute the expected value of rolling a 5 or 6 as follows:

E(X = 5\ \text{or}\ X = 6)=n\times P(X = 5\ \text{or}\ X = 6)

                               =30\times \frac{1}{3}\\\\=10

Thus, the expected value of rolling a 5 or 6 is 10.

8 0
3 years ago
The distance of planet Mercury from the Sun is approximately 5.8 ⋅ 10^7 kilometers, and the distance of planet Venus from the Su
ziro4ka [17]
Distance(Mercury, Sun) = 5.8 x 10^7
distance(Venus, Sun) = 1.1 x 10^8

distance(Venus, Mars) = 1.1 x 10^8 - 5.8 x 10^7

The subtraction is a little easier if you borrow a power of 10 from the 10^8, multiplying 1.1 by 10.

\rm 11.0\times10^7-5.8\times10^7

simply subtract 5.8 from 11.0.
This gives us a result of 5.2 x 10^7.

Hope that makes sense!
8 0
3 years ago
Read 2 more answers
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