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tino4ka555 [31]

2 years ago

15

Complete the table below.

1 answer:

STatiana [176]2 years ago

7 0

Answer:

1 2

2 3

Step-by-step explanation:

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Y=4x-6<br> 2x-3y=8<br> if this problem is to be solved by substitution , which is the correct step

Gekata [30.6K]

Answer:

x=1, y= -2

Step-by-step explanation:

Please see the attached pictures for full solution.

4 0

3 years ago

For the given circle, find the value of x

Tpy6a [65]

Answer:

230

Step-by-step explanation:

the angle 115 is half of that arc

7 0

2 years ago

A bacteria population starts with 350 bacteria and grows at a rate of r(t) = (450.267)e1.12567t bacteria per hour. how many bact

mars1129 [50]

Given that the bacteria has been modeled by the function:
r(t)=(450.267)e^(1.12567t)
thus the number of bacteria after 3 hours will be:
r(3)=450.267e^(1.12567×3)
r(3)=13,185.20623
The number of bacteria after 3 hours will be:
13, 185.20623

7 0

3 years ago

What is the midpoint of -12 and 4?

Lostsunrise [7]

Answer:

The midpoint: -4

Step-by-step explanation:

To find the midpoint between two numbers, add them together and divide by 2.

-12 + 4 = -8

-8 ÷ 2 = -4

As one formula you can write this as:

$M = \frac{-12 + 4}{2}$

$M = \frac{-8}{2}$

$M = -4$

∴ The midpoint is -4.

6 0

2 years ago

Given the acceleration, initial velocity, and initial position of a body moving along a coordinate line at time t, find the body

nika2105 [10]

Answer:

The position at time t is $s(t) = 8t^2 - 14t -8$

Step-by-step explanation:

From the question we are told that

The acceleration is $a = 16$

The velocity at t = 0 is $v(0) = -14$

The position at time t = 0 is $s(0) = -8$

Generally acceleration is mathematically represented as

$a(t) = \frac{d v}{dt }$

=> $\frac{dv}{dt} = 16$

=> $dv = 16 dt$

integrating both sides we have

$\int\limits dv = \int\limits16 dt$

=> $v(t) = 16 t + c$

Now at t = 0

$v(0) = 16 * 0 +c = -14$

=> $c = -14$

So

$v(t) = 16 t -14$

Generally the position of the body is mathematically represented as

$s(t) = \int\limits v(t)dt$

So

$s(t) = \int\limits 16t - 14 dt$

So

$s(t) = 16 \frac{t^2}{2} - 14t + C$

Now at t = 0

$s(0) = 16 \frac{0^2}{2} - 14(0) + C = -8$

=> $C = -8$

So

$s(t) = 8t^2 - 14t -8$

5 0

2 years ago