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GenaCL600 [577]
3 years ago
13

Paul received a 12,000 loan from the bank. The bank charges his 6.99% yearly interest rate. 4 years, how much money does Paul ow

e in interest
Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
8 0

Answer:ggcffdjhfr55757566656677787v  


Step-by-step explanation:


andre [41]3 years ago
5 0
Principal amount = 12,000
Annual interest rate (r) = 6.99% = 0.0699
Time (years) = 4 years
Number of installments (t) = 12*4 = 48 months

Monthly payment, A = P/D

Where,
D= {(1+r/12)^t-1}/{r/12*(1+r/12)^t} = {(1+0.0699/12)^48-1}/{0.0699/12(1+0.0699/12)^48} = 42.47

Therefore, A = 12000/42.47 = 282.59

Total payments after 4 years = 282.59*4*12 = 13,564.17

Interest owed = 13,564.17 - 12,000 = 1,564.17
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Answer:

Δ PQT ~ Δ QRS  .....{S-S-S test for similarity}...Proof is below.

Step-by-step explanation:

Given:

In Δ PQT

PQ = 30 ft

QT = 28 ft

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In Δ QRS

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RS = 14 ft

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To Prove:

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Proof:

First we consider  the ratio of the sides

\frac{PQ}{QR}=\frac{30}{15} = \frac{2}{1}            ..............( 1 )

\frac{QT}{RS}=\frac{28}{14} = \frac{2}{1}            ..............( 2 )

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So By equation ( 1 ), ( 2 ) and  ( 3 ) we get

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\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}

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