1/3(9x) =3x
1/3(18) =6
3x+6-5
Then you do
-(x)=-x
-(3)=-3
5x-x-3 = 4x-3
4x-3=3x+6-5
4x-3=3x+1
x=4
5
Step-by-step explanation:
your answer is 5 the greatest common factor is 5
10= 5
25=5
15= 5
Answer:
Step-by-step explanation:
Remark
The slope intercept line is written as y = mx + b in it's general form.
You can get the slope, m, immediately because it is given as -2
So far what you have is y = -2x + b
y intercept
To get the y intercept, use the point (-3 , 4)
x = - 3
y = 4
4 = -2*(-3) + b
4 = 6 + b Subtract 6 from both sides
4 - 6 = 6-6 + b
b = - 2
Line
y = -2x - 2
(a,8)
y = -2a - 2
8 = -2a - 2 Add 2 to both sides
8 +2 = -2a -2+2 Combine
10 = - 2a Divide by - 2
10/-2 = a
a = -5
(5,b)
y = -2x - 2
x = 5
y = b
b = -2*5 - 2
b = -10 - 2
b = - 12
Answer:
-5, -4 , -3 , -2, -1, 1, 2 , 3, 4, 5
Step-by-step explanation:
Answer:
The optimal, vertex, value will be a minimum
Step-by-step explanation:
The given zeros of the quadratic relation are 3 and 3
The sign of the second differences of the quadratic relation = Positive
Whereby the two zeros are the same as x = 3, we have that the point 3 is the optimal value or vertex (the repeated point in the graph of the quadratic relation) of the quadratic relation
Whereby, the table of values for the quadratic relation from which the second difference is found starts from x = 3, we have;
To the right of the coordinate points of the zeros of the quadratic relation, the positive second difference in y-values gives as x increases, y increases which gives a positive slope
By the nature of the quadratic graph, the slope of the line to the left of the coordinate point of the zeros of the quadratic relation will be of opposite sign (or negative). The quadratic relation is cup shaped and the zeros, therefore, the optimal value will be a minimum of the quadratic relation
