Find the complement of the angle 103º (Let me know if it's impossible. NO LINKS!!)
1 answer:
You might be interested in
1.
Consider a group of n objects. Assume we want to form groups of r, from these n objects.
There are in total
many ways of doing so.
where, r! is "r factorial", calculated as 1*2*3*...*(r-1)*r
2.
C(x, 2) is the total number of pairs out of x objects, that we can form.
so let the x objects represent the x teams, and 2, represent a group of 2, which means a game.
The total number of games is:
n(x)=2*C(x, 2) =
Remark, we multiplied by 2, since there will be 2 matches for each pair of teams.
Answer:
Consider a group of n objects. Assume we want to form groups of r, from these n objects.
There are in total
where, r! is "r factorial", calculated as 1*2*3*...*(r-1)*r
2.
C(x, 2) is the total number of pairs out of x objects, that we can form.
so let the x objects represent the x teams, and 2, represent a group of 2, which means a game.
The total number of games is:
n(x)=2*C(x, 2) =
Remark, we multiplied by 2, since there will be 2 matches for each pair of teams.
Answer:
Answer:
Step-by-step explanation:
We want to simplify:
To simplify this, we need to write the negative index as positive.
So we use the property,
When we apply this property, we get:
Therefore the fourth option is correct.