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nlexa [21]
3 years ago
12

Simplify this problem

Mathematics
1 answer:
Ksju [112]3 years ago
3 0
Hope this helps u....!!

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A car travels at a rate of 45 miles per hour for 5 hours. Let y be the distance, in miles, the car travels for a given amount of
soldi70 [24.7K]

Answer: A. 0<_ x <_ 5

Step-by-step explanation:

45 miles represents y and 5 hours amount of time represents x, you finding x-values. Your first will be 0, then <_, with x (domain:x-values), lastly 5 because 5 is an x-value and they want the domain of the function,

5 0
3 years ago
What is the constant rate of change for the relationship shown in the table?
Yakvenalex [24]

Answer:

3

Step-by-step explanation:

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3 years ago
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Which of the following best describes the expression 5(x + 2)? (1 point)
Alex73 [517]
5x+10

just distribute each value and multiply 5 to each of the values in the parentheses.
6 0
3 years ago
What are m and b in the linear equation y= 5 + 1x​
joja [24]

Answer:

m=1

y= 5

Step-by-step explanation:

since y=mx+b

y=1x+5

6 0
3 years ago
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If the 5th term of a geometric progression is 162 and the 8th term is 4374, find the (i) 1st three terms of the sequence; (ii) s
Alona [7]

Answer:

see explanation

Step-by-step explanation:

The nth term of a geometric progression is

a_{n} = a₁r^{n-1}

where a₁  is the first term and r the common ratio

Given a₅ = 162 and a₈ = 4374 , then

a₁r^{4} = 162 → (1)

a₁r^{7} = 4374 → (2)

Divide (2) by (1)

\frac{a_{1}r^{7}  }{a_{1}r^{4}  } = \frac{4374}{162}

r³ = 27

r = \sqrt[3]{27} = 3

Substitute r = 3 into (1) and solve for a₁

a₁(3)^{4} = 162

81a₁ = 162

a₁ = \frac{162}{81} = 2

Then

a₂ = a₁ × 3 = 2 × 3 = 6

a₃ = a₂ × 3 = 6 × 3 = 18

The first 3 terms are 2, 6, 18

(ii)

The sum to n terms of a geometric progression is

S_{n} = \frac{a_{1}(r^{n}-1)  }{r-1} , then

S_{10} = \frac{2(3^{10}-1) }{3-1}

     = \frac{2(59049-1)}{2}

     = 59049 - 1

     = 59048

   

6 0
3 years ago
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