Answer:
i don’t know what the instructions are but
10. K = 17
11. -w = -16
12. h = -3
Step-by-step explanation:
Answer:
Since the calculated value of t =-0.427 does not fall in the critical region so we accept H0 and conclude that there is enough evidence to show that mean difference in the age of onset of symptoms and age of diagnosis is 25 months .
Step-by-step explanation:
The given data is
Difference d= -24 -12 -55 -15 -30 -60 -14 -21 -48 -12 -25 -53 -61 -69 -80
∑ d= -579
∑d²= 29871
1) Let the hypotheses be
H0: ud= 25 against the claim Ha: ud ≠25
H0 : mean difference in the age of onset of symptoms and age of diagnosis is 25 months .
Ha: mean difference in the age of onset of symptoms and age of diagnosis is not 25 months.
2) The degrees of freedom = n-1= 15-1= 14
3) The significance level is 0.05
4) The test statistic is
t= d`/sd/√n
The critical region is ║t║≤ t (0.025,14) = ±2.145
d`= ∑di/n= -579/15= -38.6
Sd= 23.178 (using calculators)
Therefore
t= d`/ sd/√n
t= -38.6/ 23.178√15
t= -1.655/3.872= -0.427
5) Since the calculated value of t =-0.427 does not fall in the critical region so we accept H0 and conclude that there is enough evidence to show that mean difference in the age of onset of symptoms and age of diagnosis is 25 months .
Answer:
Triangle ABE and triangle CDE are congruent by using SAS theorem.
Step-by-step explanation:
It is given that e is the midpoint of BD and
.
(E is midpoint of BD)
Angle AEB and angle CED are vertical opposite angle and the vertical opposite angles are always same.
![\angle AEB\cong \angle CED](https://tex.z-dn.net/?f=%5Cangle%20AEB%5Ccong%20%5Cangle%20CED)
(Given)
So by using SAS theorem of congruent triangles.
![\triangle ABE\cong \triangle CED](https://tex.z-dn.net/?f=%5Ctriangle%20ABE%5Ccong%20%5Ctriangle%20CED)
Therefore triangle ABE and triangle CDE are congruent by using SAS theorem.
Answer:-a^2-a+12
Step-by-step explanation:
(-a+3)(a+4)
Clear brackets
-a^2-4a+3a+12
Add like terms
-a^2-a+12
Answer:
80%
Step-by-step explanation:
We are told that 1,200 students wore their school colors of green and white.
Also, we are told that 300 students did not wear school colours green and white.
Thus, total number of students = 1200 + 300 = 1500
Thus;
percent of the school population who wore their school colors is; (1200/1500) × 100% = 80%