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kompoz [17]
3 years ago
11

A school has a population of 2500 students. The number of students is increasing at continuous growth rate of 4.5% each year. Wh

ich of the following
formulas models the population of this school?
A. A = 2500e ^-0.045t
B. A = 2500e^4.5t
C. A = 2500e^0.045t
D. A = 25000e^450
Mathematics
1 answer:
Lemur [1.5K]3 years ago
6 0

Answer:

C

Step-by-step explanation:

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Solve the system by substitution. (Please Explain how you did it Ill give brainliest)
Musya8 [376]
Because the last equation already has the y eliminated so just need to get the other two to eliminate the y too

multiply 4 to the first equation to eliminate y, and you get
-4x-4y-4z=-32
-4x+4y+5z=7
now get rid of y so all you have left is
-8x+z=-25 (let call this equation #4)

now take equation #3 and #4 together to solve for one of the variables, i’ll solve for z first so i’ll get rid of x by multiply the equation #4 all by 4, you get

8x+8z=16
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done so the answer is (x,y,z) = (3,6,-1)


5 0
3 years ago
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Rita is adding 3 + (–8) + 1. She rewrites the expression as 3 + (–1) + 8. <br> What is Rita’s error?
Anna35 [415]
That the one is always positive
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Can someone help me
erik [133]

Answer:

   6 < x < 23.206

Step-by-step explanation:

To properly answer this question, we need to make the assumption that angle DAC is non-negative and that angle BCA is acute.

The maximum value of the angle DAC can be shown to occur when points B, C, and D are on a circle centered at A*. When that is the case, the sine of half of angle DAC is equal to 16/22 times the sine of half of angle BAC. That is, ...

  (2x -12)/2 = arcsin(16/22×sin(24°))

  x ≈ 23.206°

Of course, the minimum value of angle DAC is 0°, so the minimum value of x is ...

  2x -12 = 0

  x -6 = 0 . . . . . divide by 2

  x = 6 . . . . . . . add 6

Then the range of values of x will be ...

  6 < x < 23.206

_____

* One way to do this is to make use of the law of cosines:

  22² = AB² + AC² -2·AB·AC·cos(48°)

  16² = AD² + AC² -2·AD·AC·cos(2x-12)

The trick is to maximize x while satisfying the constraints that all of the lengths are positive. This will happen when AB=AC=AD, in which case the equations be come ...

  22² = 2·AB²·(1-cos(48°))

  16² = 2·AB²·(1 -cos(2x-12))

The value of AB drops out of the ratio of these equations, and the result for x is as above.

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3 years ago
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Daniel left a $9 tip for the waiter at a restaurant. If the tip was 15 percent of the bill, how much was the bill?
Pie
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3 years ago
Given log4(3) =0.7925 and log4(5) =1.1610, use log properties to find log4(300).
Ede4ka [16]

Answer:

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Step-by-step explanation:

You can use the following formula to solve this kind of problems,

log_{a}(b)  +  log_{a}(c)  =  log_{a}(bc)

So, let's start of with log4_(300). Since the question have already gave log4_(3) =0.7925 and log4_(5) =1.1610. It means that you have to split the 300 into the simplest form where almost all of the numbers are 3 and 5.

log_{4}(300)  =  log_{4}(4 \times 5 \times 3 \times 5)  \\  =  log_{4}(4)  + log_{4}(5)  + log_{4}(3)  + log_{4}(5)  \\   = 1 + 1.1610 + 0.7925 + 1.1610 \\  = 4.1145

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3 years ago
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