Answer:
d) 205
Step-by-step explanation:
<u><em>Step(i):-</em></u>
x : 100 150 200 250 300
p(X=x) : 0.10 0.20 0.30 0.30 0.10
<u>Step(ii):-</u>
Let 'X' be the discrete random variable
Expected value of the random variable
E(X) = ∑ x P(X=x)
= 100 X 0.10 + 150 X 0.20 + 200 X 0.30 +250 X 0.30 + 300 X 0.10
= 205
<u>Final answer:</u>-
The expected value E(X) = 205
The first one!! it should be correct
There are four aces, 12 face cards and 4 7s in a standard 52 card deck. The probability of getting an ace on the first draw is 4/52 or 1/13. For the second draw there are now 51 cards in the deck (assuming the draws are without replacement), so the probability of getting a face card is 12/51. Given an ace and a face card on the first two draws, the probability of a 7 on the third draw is 4/50 or 2/25. The probability of getting all three is 1/13*12/51*2/25.
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80$ because 50 divided by 3 is 16.67 and 80 divided by 5 is 16 so yeah $80
Answer:
100 minutes and yes
Step-by-step explanation:
