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3 years ago

Ray BD bisects 2ABC. Use the diagram and the given angle measure to

Mathematics

1 answer:

Alenkinab [10]3 years ago

5 0

Assuming you mean angle ABC and not 2ABC?
Since ray BD bisects angle ABC we can set the two angle measures given equal to each other.
2x+7=4x-41
Solve for x=24
Plug in the x to find angle ABD 2(24)+7=55
therefore angle ABD is 55 and angle DBC is 55 so angle ABC is 110

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Nora got an allowance of 50¢ each weekday and 75¢ each weekend altogether how much do they get in:

Furkat [3]

A) > since it is 50c per weekday and 75c each weekend assuming it allows for the 2 days each saturday/sunday.
50c * 5 = $2.50 since there are 5 days in weekdays
75c * 2 = $1.50 since there are 2 days in the weekend
Add $2.50 and $1.50 to get $4.00

b) For 3 school days we know it is a weekday on the school week.
So perform 50c * 3 which gives us $1.50

c) 12 days off from school is 10 weekdays and 1 weekend or 2 days of 75c
So now just do 50c * 10 which is $5.00 and 75c * 2 which is $1.50
Add $5.00 and $1.50 and we get $6.50

d) 4 weeks = 20 weekdays since 5 *4 = 20 and 8 days in each weekend since 2 * 4 = 8
Now that we have the amount of weekdays and weekend days we can multiply.
50c * 20 = $10.00
75c * 4 = $3.00
Add $10.00 and $3.00 to get $13.00 for 4 weeks.

e) We have 1 day of the weekend and 2 weekdays here.
50c * 2 = $1.00
75c * 1 = 75c
$1.00 + 75c = $1.75 in those 3 days listed.

Add all these together to get your total value.
$4.00 + $1.50 + $6.50 + $13.00 + $1.75 = $26.75

7 0

3 years ago

Use the three steps to solve the problem. maple syrup worth $6.00 a gallon and corn syrup worth .80 cents a gallon are used to m

Ksenya-84 [330]

Cost of maple syrup = $6.00 a Gallon Cost of corn syrup = 0.80 cents a Gallon Cost of the syrup mixture = $2.36 a Gallon There is mixture of 50 Gallons Lets maple syrup be x gallons, so corn syrup be 50-x gallons Hence, 6*x + 0.80(50-x) = 2.36*50 6x + 40 - 0.8x = 118 5.2x = 78 => x = 78/5.2 => x = 15 So Maple will be syrup be 15 gallons. Corn syrup will be 35 gallons.

3 0

3 years ago

Question 28 of

Helen [10]

$y - y1 = m(x - x1) \\ y - 8 = 15(x - 2) \\ y - 8 = 15x - 30 \\ y = 15x - 30 + 8 \\ y = 15x - 22$

The equation of line is y = mx+b ; m is slope , b is y- intercept

Please give brainlest

7 0

2 years ago

Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of

IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if n = 100.

(2) A Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable X following a Binomial distribution with parameters n and p.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.10=1$

Thus, a Normal approximation to binomial can be applied for population 1, if n = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

8 0

3 years ago

Find the simple interest on $2,219 principal, deposited for 6 years at a rate of 1.91%

Aleks04 [339]

Answer:

$13,568.30

Step-by-step explanation:

I = Prt

I = 2,219(1.0191)(6) = 13,568.30

6 0

3 years ago