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Lena [83]
3 years ago
10

About 1919​% of the population of a large country is nervous around strangersnervous around strangers. if two people are randoml

y​ selected, what is the probability both are nervous around strangersnervous around strangers​? what is the probability at least one is nervous around strangersnervous around strangers​?
Mathematics
1 answer:
Pani-rosa [81]3 years ago
6 0

<span>Probability that a person is math phobic = 19% = 19/100 
a) the probability that both are nervous around strangers</span>

<span>P (A) 
= 19/100 * 19/100 
= 361/10000 
= 0.0361</span>

<span>
b) The probability that both are not nervous around strangers</span>

<span>P (B) = 81/100 * 81/100 
= 0.6561</span>

<span>
The probability that at least one person is nervous around strangers i.e. P'(B) = 1 - P(B) 
= 1 - 0.651
= 0.3439</span>

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Triss [41]

<u>Corrected Question</u>

Ping lives at the corner of 3rd Street and 6th Avenue. Ari lives at the corner of 21st Street and 18th Avenue. There is a gym 2/3 the distance from Ping's home to Ari's home.  Where is the gym?

  • 9th Street and 10th Avenue
  • 12th Street and 12th Avenue
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Answer:

(D)15th Street and 14th Avenue

Step-by-step explanation:

Ping's Location: (3rd Street, 6th Avenue)

Ari's Location: (21st Street, 18th Avenue)

The gym is at point P which is \dfrac{2}{3} the distance from Ping's home to Ari's home.

That is, Point P divides the line segment in the ratio 2:1.

We use the section formula:

(x,y)=\left(\dfrac{mx_2+nx_1}{m+n}, \dfrac{my_2+ny_1}{m+n}\right)

m:n=2:1, (x_1,y_1)=(3,6), (x_2,y_2)=(21,18)

=\left(\dfrac{2*21+1*2}{2+1}, \dfrac{2*18+1*6}{2+1}\right)\\=\left(\dfrac{45}{3}, \dfrac{42}{3}\right)\\=(15,14)

The gym is located at 15th Street and 14th Avenue.

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280 x 358 = <u>100,240</u> .

You can tell right away that this is the smallest one that qualifies,
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3 years ago
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