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dalvyx [7]
2 years ago
13

Segment addition postulate What’s the answer?

Mathematics
1 answer:
Free_Kalibri [48]2 years ago
3 0

\bf Step-by-step~explanation:

Keep in mind: The entire line segment (VX) is equal to 14.

\bf Step~1:

Let's see how the line segment looks like first.

Line segment VX is 14 units long.

             14

______________

V                         X

W is on the line segment somewhere, and VW is equal to 3.

     3              ?

______________

V           W           X

\bf Step~2:

We have to solve for the <em>?.</em> Let's put ? as x. So now we are solving for x.

We have to set up our equation like this:

x + 3 = 14

Since our unknown value plus 3 is equal to 14, we have to subtract 3 from 14 to get our answer.

14 - 3 = 11

   3               11

______________

V           W           X

\large\boxed {\bf Our~final~answer: ~WX=11}

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Radda [10]

Answer:

TU and TS (with arrows on top)

Step-by-step explanation:

The sides of any angle are rays. This are half lines, which in your case both start at the point T, and one goes towards point U, while the other one goes from toward point S. So I would write TU (with a little arrow symbol on top). and in the other box I would write TS also with a little arrow symbol on top.

5 0
3 years ago
What is the mean of this table
suter [353]

Answer:

The mean is 77.8125

Step-by-step explanation:

The mean is the average of the numbers. It is very easy to calculate and get. All you have to do is add up all the numbers and divide it by how many numbers there are.

80 + 90 + 81 + 86 + 100 + 77 + 75 + 96 + 65 + 87 + 58 + 80 + 36 + 73 + 70 + 91 = 1245

\frac{1245}{16} = 77.8125

7 0
3 years ago
Match the polynomial expression on the left with the simplified version on the right.
Vitek1552 [10]

Given the following question:

First expression:

\begin{gathered} \frac{12x^3-14x^2+16x-8}{3x-2} \\ \text{ Factor the expression:} \\ 12x^3-14x^2+16x-8=2(6x^3-7x^2+8x-4) \\ \frac{2\left(6x^3-7x^2+8x-4\right)}{3x-2} \\ \text{ Factor:} \\ 2\left(6x^3-7x^2+8x-4\right)=(3x-2)(2x^2-x+2) \\ =(3x-2)(2x^2-x+2)=2\left(3x-2\right)\left(2x^2-x+2\right) \\ \frac{2\left(3x-2\right)\left(2x^2-x+2\right)}{3x-2} \\ \text{ Cancel the common factor:} \\ -(3x-2) \\ 4x^2-2x+4 \end{gathered}

Second expression:

3 0
1 year ago
Determine the values of the requested variables
Dafna1 [17]

Answer:

y = 24

angle V = 67

as a 4 sided shape, the angles all have to add up to 360 degrees.

we already have the answers for R, 120, and B, 53. We have 187 degrees left to work with.

Based of the information the tics on the sides of the figure gives us, we know that angle P and R are the same! First (just for fun, this isn't needed) we'll find X.

(x+95) = 120

   -95     -95

       x = 25

We know 3/4 angles now, so by subtracting their sum from 360, we'll find angle V!

360 - 53 -120 - 120 = 67

Angle V is 67

Now to find y!

(2y+19)=67

     -19  -19

     2y = 48

     /2     /2

       y = 24

7 0
2 years ago
Given P = x^0.3 y^0.7 is the chicken lay eggs production function, where P is the number of eggs lay, x is the number of workers
lora16 [44]

Answer:

Part A)

\displaystyle \frac{dy}{dx}=-\frac{3}{7}P^\frac{10}{7}x^{-\frac{10}{7}}

Part B)

The daily operating cost decreases by about $143 per extra worker.

Step-by-step explanation:

We are given the equation:

\displaystyle P=x^{\frac{3}{10}}y^{\frac{7}{10}}

Where <em>P</em> is the number of eggs laid, <em>x</em> is the number of workers, and <em>y</em> is the daily operating budget (assuming in US dollars $).

A)

We want to find dy/dx.

So, let’s find our equation in terms of <em>x</em>. We can raise both sides to 10/7. Hence:

\displaystyle P^\frac{10}{7}=\Big(x^\frac{3}{10}y^\frac{7}{10}\Big)^\frac{10}{7}

Simplify:

\displaystyle P^\frac{10}{7}=x^\frac{3}{7}y

Divide both sides by<em> </em>the <em>x</em> term to acquire:

\displaystyle y=P^\frac{10}{7}x^{-\frac{3}{7}}

Take the derivative of both sides with respect to <em>x: </em>

\displaystyle \frac{dy}{dx}=\frac{d}{dx}\Big[P^\frac{10}{7}x^{-\frac{3}{7}}\Big]

Apply power rule. Note that P is simply a constant. Hence:

\displaystyle \frac{dy}{dx}=P^\frac{10}{7}(-\frac{3}{7})(x^{-\frac{10}{7}})

Simplify. Hence, our derivative is:

\displaystyle \frac{dy}{dx}=-\frac{3}{7}P^\frac{10}{7}x^{-\frac{10}{7}}

Part B)

We want to evaluate the derivative when <em>x</em> is 30 and when <em>y</em> is $10,000.

First, we will need to find <em>P</em>. Our original equations tells us that:

P=x^{0.3}y^{0.7}

Hence, at <em>x</em> = 30 and at <em>y</em> = 10,000, <em>P </em>is:

P=(30)^{0.3}(10000)^{0.7}

Therefore, for our derivative, we will have:

\displaystyle \frac{dy}{dx}=-\frac{3}{7}\Big(30^{0.3}(10000^{0.7})\Big)^\frac{10}{7}\Big(30^{-\frac{10}{7}}\Big)

Use a calculator. So:

\displaystyle \frac{dy}{dx}=-\frac{1000}{7}=-142.857142...\approx-143

Our derivative is given by dy/dx. So, it represents the change in the daily operating cost over the change in the number of workers.

So, when there are 30 workers with a daily operating cost of $10,000 producing a total of about 1750 eggs, the daily operating cost decreases by about $143 per extra worker.

5 0
2 years ago
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