Segment addition postulate What’s the answer?
1 answer:
Keep in mind: The entire line segment (VX) is equal to 14.
Let's see how the line segment looks like first.
Line segment VX is 14 units long.
14
______________
V X
W is on the line segment somewhere, and VW is equal to 3.
3 ?
______________
V W X
We have to solve for the <em>?.</em> Let's put ? as x. So now we are solving for x.
We have to set up our equation like this:
x + 3 = 14
Since our unknown value plus 3 is equal to 14, we have to subtract 3 from 14 to get our answer.
14 - 3 = 11
3 11
______________
V W X
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Answer:
C.
Step-by-step explanation:
Domain is only affected if certain values can make the result something that either doesn't make sense or is an error. In your situation, it wants you to find the domain of f/g, which is a fraction. The only rule we have for fractions regarding domain is that we simply can't divide by zero, to find the domain for any fraction with variables in the denominator, what I do is take the denominator, set it equal to 0, and solve for x.
So, if we're taking f/g, we have:
4x - 3 makes up our denominator, the bottom part of the fraction. So
4x - 3 = 0
4x = 3
x = 3/4
So the denominator is equal to zero when x is equal to 3/4. This would produce an error in any calculator because you can't divide by zero. The domain here is all real numbers except for 3/4.
(For future problems, the only thing to look out for is if your numerator, the top part of the fraction, factors into something that cancels with the bottom. In that case, it wouldn't affect domain because you aren't actually dividing by anything. For example:
If we factor the top, we see that x^2 - 4 = (x - 2)(x + 2). In this case, we have (x - 2) in both the top and bottom of the fraction, so it cancels out, and from there nothing else is restricting our domain. It would be all real numbers in a case like that.)