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3 years ago

7

Write 4,670,000 in standard form

2 answers:

GrogVix [38]3 years ago

8 0

Step-by-step explanation:

4,670,000

->

4.67x10^6

(im pretty sure this is correct) :)

Alex_Xolod [135]3 years ago

7 0

Answer:

<h3>4.67×10 power 6</h3>

I hope it helps

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3 years ago

Determine whether each expression can be used to find the length of side AB. Match Yes or No for each

tankabanditka [31]

Answer:

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

Step-by-step explanation:

Given

$BC =24$

$AC = 7$

Required

Select Yes or No for the given options

$(a)\ AB = \frac{7}{\sin (B)}$ $\to Yes$

Considering the sine of angle B, we have:

$\sin(B) = \frac{Opposite}{Hypotenuse}$

$\sin(B) = \frac{7}{AB}$

Make AB, the subject

$AB = \frac{7}{\sin(B)}$

$(b)\ AB = \frac{24}{\cos (B)}$ $\to Yes$

Considering the cosine of angle B, we have:

$\cos(B) = \frac{Adjacent}{Hypotenuse}$

$\cos(B) = \frac{24}{AB}$

Make AB the subject

$AB = \frac{24}{\cos(B)}$

$(c)\ AB = \frac{24}{\cos (A)}$ $\to No$

Considering the cosine of angle B, we have:

$\cos(A) = \frac{Adjacent}{Hypotenuse}$

$\cos(A) = \frac{7}{AB}$

Make AB the subject

$AB = \frac{7}{\cos(A)}$

$(d)\ AB = \frac{7}{\cos (A)}$ $\to Yes$

<em>This has been shown in (c) above</em>

3 0

3 years ago

A man is four times as old as his son. 10 years later, the man will be three times as old as his son. What is the man’s current

kvasek [131]

Answer:

The son is 20 and the father is 80.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Help me ASAP PLEASE

tamaranim1 [39]

Answer:

Your(my) number is 40

Step-by-step explanation:

I. Given 80/something, + 13, * 5 = 75 when x is something

So [ $\frac{80}{x}$ + 13 ]5 = 75

[ $\frac{400}{x}$ + 65] = 75

$\frac{400}{x}$ = 75 - 65

$\frac{400}{x}$ = 10

400 = 10x

x = 40

II. Prove by replace 40 in x

[(80/40) + 13]5 = 75

[2 + 13] 5 = 75

(15)5 = 75

75 = 75 true

Ask me for anything.

5 0

2 years ago