Answer:
C, D and E
Step-by-step explanation:
Assuming
f(x) = √(9−8x)
and the options are:
A. p(x) = √(-8x) and q(x)=9+x
B. p(x) = √(9+x) and q(x)=8x
C. p(x) = √(-x) and q(x)=8x−9
D. p(x)=√(9−x) and q(x)=8x
E. p(x)=√x and q(x)=9−8x
F. p(x)=9−8x and q(x)=√x
G. All of the above
H. None of the above
Substituting in f(x)=p(q(x)) we get:
A. √(-8(9+x)) = √(-72 - 8x)
B. √(9+(8x)) = √(9+8x)
C. √(-(8x−9
)) = √(-8x + 9)
D. √(9−(8x)) = √(9−8x)
E. √(9−8x
)
F. 9−8(√x
) = 9 - 8√x
Here is the answer to your problem
Answer:
Ok,
Did you know that there was a chicken that went 4 years without a head?
Did you know that it is illegal to chew gum in Signapore?
Step-by-step explanation:
Hope this brightens your day!
The smallest region that can be photographed is
5*7 = 35 square km
so we want to know how long it takes to zoom out to an area of
35 * 5 = 175 square km.
Notice that the length and width increase at the same rate, 2 km/sec, and they start out with a difference of two, so when the width has increased from 5 to x, the length will have increased from 7 to x+2. At the desired coverage area, then,
x(x+2) = 175
x^2 + 2x = 175
x^2 + 2x + 1 = 176 [completing the square]
(x+1)^2 = 176
x+1 = ±4√11
x = -1 ±4√11
Since a negative value for x is meaningless here, x must be
-1 + 4√11 = about 12.27 km
and the time it took to increast to that value was
(12.27 - 5) km / (2 km/sec) = about 3.63 seconds
Answer:
8640 square inches
Step-by-step explanation:
There are 12 inches in one foot so there would be 12 * 12 = 144 square inches in 1 square foot. Therefore, there are 144 * 60 = 8640 square inches in 60 square feet.
