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mezya [45]
3 years ago
15

I need help asap i’ll give brainliest

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
5 0

Answer:

x=130 I believe

Step-by-step explanation:

28+8+14+x=180

50+x=180

x=130

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4 years ago
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J has coordinates of (10,-2) and N has Coordinates of (-4,6). Find the midpoint of JN.
Thepotemich [5.8K]

Midpoint of JN is at coordinates (3,2)

Step-by-step explanation:

Coordinates of j= (10,-2)

Coordinates of N = (-4,6)

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The formula used to find midpoint is:

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

We are given:

x_1=10,x_2=-4,y_1=-2,y_2=6

Putting values and finding midpoint of JN

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

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Midpoint=(\frac{6}{2},\frac{4}{2})

Midpoint=(3,2)

So, midpoint of JN is at coordinates (3,2)

Keywords: Midpoint of line

Learn more about Midpoint of line at:

  • brainly.com/question/3269852
  • brainly.com/question/1473992
  • brainly.com/question/909890

#learnwithBrainly

8 0
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