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3 years ago

Evaluate. 5.002 - 4.3

Mathematics

2 answers:

salantis [7]3 years ago

8 0

The answer is 0.702 :) hope this helps

tia_tia [17]3 years ago

3 0

Answer:

0.702

Step-by-step explanation:

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Responda abaixo: a)2x+3y=10*√4 b)x+2y+5*3=x+y

RoseWind [281]

Answer:

a) x = 10 + -1.5y

b) y+15

Step-by-step explanation:

a)2x+3y=10*√4

2x+3y=20

2x + 3y + -3y = 20 + -3y

2x + 0 = 20 + -3y

2x = 20 + -3y

x ÷ 2 = (20 + -3y) ÷2

x = 10 + -1.5y

b)x+2y+5*3=x+y

x+2y+15=x+y

x+2y+15 - y=x+y - y

x+y+15 =x

x+y+15 - x =x - x

y+15

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4 years ago

After Lin makes her way down the hallway, will locker number 56 have 0 magnets, 1 magnet, or both magnets?

Law Incorporation [45]

Answer:

0 magnets

Step-by-step explanation:

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3 years ago

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What is this equation equal -4x+3x=2

Zarrin [17]

Answer:

x=2

Step-by-step explanation:

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3 years ago

GIVING AWAY 35 POINTS! What is the graph of this function?

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Im pretty sure its graph A

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3 years ago

A box contains eighteen $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill. You blindly reach into the

zubka84 [21]

Answer: $7.70

Step-by-step explanation:

Given : A box contains eighteen $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill.

Total bills = $18+10+8+3+1=40$

We know that probability of any event = $\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}$

i.e. the probability of getting $1 bills = $P(E_1)=\dfrac{18}{40}=0.45$

Probability of getting $10 bills = $P(E_2)=\dfrac{10}{40}=0.25$

Probability of getting $5 bills = $P(E_3)=\dfrac{8}{40}=0.2$

Probability of getting $20 bills = $P(E_4)=\dfrac{3}{40}=0.075$

Probability of getting $100 bills = $P(E_5)=\dfrac{1}{40}=0.025$

$\text{Expected value =}1\times P(E_1)+5\times P(E_2)+10\times P(E_3)+20\times P(E_4)+100\times P(E_5)\\\\=1\times 0.45+5\times 0.25+10\times0.2+20\times 0.075+100\times 0.025\\\\=7.7$

Hence, the expected value of your draw= $7.70

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4 years ago

Evaluate. 5.002 - 4.3 ￼

Evaluate. 5.002 - 4.3