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tangare [24]
2 years ago
7

Evaluate. 5.002 - 4.3 

Mathematics
2 answers:
salantis [7]2 years ago
8 0
The answer is 0.702 :) hope this helps
tia_tia [17]2 years ago
3 0

Answer:

0.702

Step-by-step explanation:

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Connie bought 172 tulip bulbs. She wants to plant an equal number of bulbs in each of 4 flower beds. How many bulbs should Conni
Levart [38]

Answer:

43

Step-by-step explanation:

172/4= 43

4 0
3 years ago
Triangle angle sum theorem<br> What is the value of z?
prisoha [69]

Answer:

z=3

Step-by-step explanation:

→32+76+24z=180[Sum of all sides of a triangle]

→108+24z=180

→24z=180-108

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7 0
2 years ago
Read 2 more answers
A lumber yard has scrap wood for sale. One employee recorded the measurements for the lengths of 50 different wood boards. The m
marusya05 [52]

Answer:

The updated IQR is 14.54.

Step-by-step explanation:

The interquartile range is given by the difference between the 75th percentile(value that is greater than 75% of the measures) and the 25th percentile.

This means that each piece of wood is actually 5 inches shorter than the value recorded by the employee.

This means that the length of each wood is less than 5. However, the difference between the 75th percentile and the 25th percentile will stay the same, since both were subtracted by 5.

The updated IQR is 14.54.

5 0
2 years ago
What is the solution to 3.25x + 1 − 4.25x = −2?
Dovator [93]

Answer:

x = 3

Step-by-step explanation:

7 0
2 years ago
Help, my daughter is learning about finding lengths of unknown sides. I have no idea how to help on these three homework problem
Lyrx [107]
BC = 4
GE= 23
QR = 7
TR = 11
BD = 22
FG = 6

explanation: you have to look at the numbers at the opposite side of where it’s asking, for example the first one; on the opposite side of BC it’s 12 and other side is 8 and you have to find the space in between so to find BC you would have to subtract 12-8 and you’ll get 4
basically a bunch of subtraction and addition, just look at the numbers on the opposite side. hope this helps !
5 0
2 years ago
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