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tatyana61 [14]
3 years ago
5

Find the distance between A and B.

Mathematics
2 answers:
Flura [38]3 years ago
7 0

The answer is D. 10 units.

professor190 [17]3 years ago
6 0

Answer:

C

Step-by-step explanation:

distance formula

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4 0
3 years ago
If a point P(x,y) is the equidistant from the points A(2,3) and B(6,1), find the equation of locus of moving point P.​
jekas [21]

Answer:

y=2x-6

Step-by-step explanation:

A locus can be defined as a curve or figure formed by all the points satisfying a particular equation of the relation between coordinates.

The condition stated in the question is such that a generic (x,y) point of the curve is equidistant from the points A(2,3) and B(6,1).

The distance d1 from (x,y) to (2,3) is:

d_1=\sqrt{(x-2)^2+(y-3)^2}

The distance d2 from (x,y) to (6,1) is:

d_2=\sqrt{(x-6)^2+(y-1)^2}

Since d1=d2:

\sqrt{(x-2)^2+(y-3)^2}=\sqrt{(x-6)^2+(y-1)^2}

Squaring both sides:

(x-2)^2+(y-3)^2=(x-6)^2+(y-1)^2

Operating:

x^2-4x+4+y^2-6y+9=x^2-12x+36+y^2-2y+1

Simplifying all the squares:

-4x+4x+4-6y+9=-12x+36-2y+1

Moving the variables to the left side and the numbers to the right side:

-4x+12x-6y+2y=36+1-4-9

Simplifying:

8x-4y=24

Dividing by 4:

2x-y=6

Or, equivalently:

\boxed{y=2x-6}

7 0
3 years ago
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