Answer:
h = 61.25 m
Step-by-step explanation:
It is given that,
The initial velocity of the ball, v = 60 m/s
It is thrown from a height of 5 feet, 
We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

Putting all the values,
.....(1)
For maximum height, put

Put t = 1.875 in equation (1)

So, the maximum height reached by the ball is 61.25 m.
Found this on google to help you out but it states “ Find the first derivative of a function f(x) and find the critical numbers. Then, find the second derivative of a function f(x) and put the critical numbers. If the value is negative, the function has relative maxima at that point, if the value is positive, the function has relative maxima at that point.”
Answer:
1. For a cube, volume = 
2.
= edge
3. Volume of the cube = 216 so, the edge =
= 6
4. 1st blank = 6
2nd blank = 6
3rd blank = 216
4th blank = 216
5. 6 is the edge
6. As the room is a square and we have to find the side
Area = 121
Edge =
= 11
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