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ivolga24 [154]
2 years ago
10

The point slope equation of a line is

Mathematics
2 answers:
vivado [14]2 years ago
5 0

Answer:

y-y1=m (x-x1)

Step-by-step explanation:

I hope this is what you're looking for!

EastWind [94]2 years ago
3 0

Step-by-step explanation:

Point-slope is the general form y-y₁=m(x-x₁) for linear equations. It emphasizes the slope of the line and a point on the line (that is not the y-intercept).

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It is your first semester at college and you take out a $5000 loan and in order to pay off that loan by the end of the semester
kakasveta [241]

Answer:

5000-1250x

Step-by-step explanation:

All you need to do is find the amount of money you get paid a month and use variable x to represent the months and then subtract that from the money you need to pay off.

8 0
3 years ago
A 100 pound person on Earth would weigh about 4x4x4x4 pounds on Jupiter. Evaluate the expression to determine how much a 100 pou
e-lub [12.9K]
256 pounds on Jupiter
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Read 2 more answers
Please Solve This Problem For Me<br><br> x^2 + 5^2 = 7^2<br><br> (^2 Means Squared)
Triss [41]
X^2+5^2=7^2
x^2+25=49
(49-25)
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sqrt(24)=4.89897948557
7 0
3 years ago
3 questions in 1
MrRissso [65]

Answer:

1. D. 20, 30, and 50

2. A. 86

3. B. 94

Step-by-step explanation:

1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.

The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.

Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.

Thus:

Q1 = (85 + 87)/2 = 86

Q3 = (93 + 95)/2 = 94

IQR = Q3 - Q1 = 94 - 86

IQR = 8

Outliers in the data set are data values below the lower limit or above the upper limit.

Let's find the lower and upper limit.

Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74

The data values below the lower limit (74) are 20, 30, and 50

Let's see if we have any data value above the upper limit.

Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106

No data value is above 106.

Therefore, the only outliers of the data set are:

D. 20, 30, and 50

2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.

Thus:

Q1 = (85 + 87)/2 = 86

3. Q3 = (93 + 95)/2 = 94

3 0
2 years ago
You have a math test. you plan to study 5/6 hour tonight and 3/4 hour tomorrow.
alekssr [168]

5/6 of an hour is 50 Minutes

3/4 of an hour is 45 Minutes

6 0
3 years ago
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