Q: Three planes are flying parallel to one another. The distance between plane 1 and plane 2 is half the distance between plane
2 and plane 3. Plane 2 is flying along the path given by the equation 3x-4y=17. When plane 1 is at the point (4,5), how far (in metres) is plane 2 from plane 3? *Ik the answer is 10 metres but how do you get the answer?*
The answer to the problem is C 2^12 the reason is because 16^3 is 4,096 and 2^7=128 2^11=2,048 2^12=4,096 which is what we want so this is the answer 2^64=18,447,744,073,709,551,616 which is not even close to what we want at all
