8.544 is the sqare root with a remainder
Answer:
∠ p ≈ 59°
Step-by-step explanation:
Using Pythagoras' identity in right triangle ABD to find DB
DB² = 5² + 6² = 25 + 36 = 61 ( take square root of both sides )
DB = 
---------------------------------------
Using the cosine ratio in right triangle DBC
cos p = 
= 
= 
, thus
p = 
( ) ≈ 59°
Answer:
a = -8
Step-by-step explanation:
-5⁄2 a + 5 = 25
Subtract 5 from each side
-5⁄2 a + 5-5 = 25-5
-5/2 a = 20
Multiply each side by -2/5 to isolate a
-2/5 * -5/2 a = -2/5 *20
a = -8
Draw out a horizontal line. Place 0 at the center. Then place evenly spaced tick marks on either side of 0. Label the right side of tick marks as 1, 2, 3, ... moving from 0 and going to the right
Label the left side of tick marks -1, -2, -3, ... starting at 0 and moving left
The location -3 on the number line is exactly 3 units away from 0. We start at 0 and move to -3 by moving 3 spots to the left; or we start at -3 and move 3 units to the right to get to 0.
Therefore, the absolute value of -3 is 3
Absolute value on a number line is the distance a number is from 0
The distance is never negative
The correct answer is 1.0906
