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Anarel [89]
3 years ago
6

What is the x, y, and z for this question?

Mathematics
1 answer:
Monica [59]3 years ago
4 0

Answer:

x= -2

y=0

z= 1

Step-by-step explanation:

{-x+5y-10z=-8

2x-y+10z=6}

{2x-y+10z=6

-7x-3y-10y=4}

{-x+5y-10z=-8

2x-y+10z=6} = x+4y=-2

{2x-y+10z=6

-7x-3y-10y=4} = -5x-4y=10

{x+4y=-2

-5x-4y=-10}. =. y= 0 x= -2

substitute x and y in -x+5y-10z=-8

-(-2)+5(0)-10z=-8

solve for z

z= 1

(x,y,z) = (-2,0,1)

hope this helps

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If we begin with the first term, 2, mult. it by 4 and then subtract 3, we get 5 (not 4, as shown).

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If we begin with 13, mult. it by 4 and then subtract 3, we get 49. This agrees with the terms of the given sequence.

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