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kifflom [539]
2 years ago
8

What is the slope of the line that passes through the points (-5, -7)(−5,−7) and (4, -1) ?(4,−1)? Write your answer in simplest

form.
Mathematics
2 answers:
Anika [276]2 years ago
7 0

Answer:

The slope is 6/9.

Step-by-step explanation:

The equation used to calculate the slope from two points is:

(y2 - y1) ÷ (x2 - x1) =

It <u>doesn't matter</u> which x or y you choose to be first since <u>you'll get the same answer</u>. (For me, it's easier to go with the bigger number as the second x & y, so that's what I did.)

(-1 - -7) ÷ (4 - -5) = <u>6/9</u>

ruslelena [56]2 years ago
7 0

Answer:

i would help you but i do not know it

Step-by-step explanation:

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Can u help me figure out this question plz
Dmitry [639]
Rectangle = 9*5=45
Triangle= 1/2 * 10 * 3 = 15
Add the two shapes: 45+15 = 60 sq units
4 0
3 years ago
B) Let g(x) =x/2sqrt(36-x^2)+18sin^-1(x/6)<br><br> Find g'(x) =
jolli1 [7]

I suppose you mean

g(x) = \dfrac x{2\sqrt{36-x^2}} + 18\sin^{-1}\left(\dfrac x6\right)

Differentiate one term at a time.

Rewrite the first term as

\dfrac x{2\sqrt{36-x^2}} = \dfrac12 x(36-x^2)^{-1/2}

Then the product rule says

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 x' (36-x^2)^{-1/2} + \dfrac12 x \left((36-x^2)^{-1/2}\right)'

Then with the power and chain rules,

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12\left(-\dfrac12\right) x (36-x^2)^{-3/2}(36-x^2)' \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} - \dfrac14 x (36-x^2)^{-3/2} (-2x) \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12 x^2 (36-x^2)^{-3/2}

Simplify this a bit by factoring out \frac12 (36-x^2)^{-3/2} :

\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-3/2} \left((36-x^2) + x^2\right) = 18 (36-x^2)^{-3/2}

For the second term, recall that

\left(\sin^{-1}(x)\right)' = \dfrac1{\sqrt{1-x^2}}

Then by the chain rule,

\left(18\sin^{-1}\left(\dfrac x6\right)\right)' = 18 \left(\sin^{-1}\left(\dfrac x6\right)\right)' \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac x6\right)'}{\sqrt{1 - \left(\frac x6\right)^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac16\right)}{\sqrt{1 - \frac{x^2}{36}}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{3}{\frac16\sqrt{36 - x^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18}{\sqrt{36 - x^2}} = 18 (36-x^2)^{-1/2}

So we have

g'(x) = 18 (36-x^2)^{-3/2} + 18 (36-x^2)^{-1/2}

and we can simplify this by factoring out 18(36-x^2)^{-3/2} to end up with

g'(x) = 18(36-x^2)^{-3/2} \left(1 + (36-x^2)\right) = \boxed{18 (36 - x^2)^{-3/2} (37-x^2)}

5 0
2 years ago
find two consecutive odd integers that 7 times the smaller integer is 61 more than 2 times the larger integer.
Aleks04 [339]

Answer:

x = 13     smaller integer

x + 2 = 15  the other integer

Step-by-step explanation:

x = the smaller integer

x + 2 = the next integer          

7(x) = 61 + 2(x + 2)

7x = 61 + 2x +4

5x = 61 + 4

5x  = 65

x = 13     smaller integer

x + 2 = 15  the other integer

8 0
2 years ago
Jennifer's saving to buy a bike. The bike costs $245. She has $125 saved, and each week she adds $15 to her savings. How long wi
Novosadov [1.4K]
It will take her 8 weeks to save up enough money for the bike.

To get the answer first you have to subtract 125 from 245 to see how much money she still has to save then divide the answer which is 120 by 15 and you get 8. Hope this helps!!
4 0
2 years ago
Read 2 more answers
Subtract the binomials. On simplifying (-3y2 − 8) − (-5y2 + 1), we get ____ y2 −______ .
Gala2k [10]
(-3y^2 − 8) − (-5y^2<span> + 1)
= </span>-3y^2 − 8 + 5y^2<span> - 1
= 2</span>y^2 <span>- 9

answer is

</span>2y^2 - 9<span>

</span>
6 0
3 years ago
Read 2 more answers
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