Answer:
96cm^2
Step-by-step explanation:
We can divide it into two rectangles: 7x8 and 10x(12-8), arriving at the solution of 7cm*8cm + 10cm*4cm = 56cm^2 + 40cm^2 = 96cm^2
We can also divide it into two rectangles: 12x7 + (12-8)x(10-7), arriving at 12cm*7cm + 4cm*3cm = 84cm^2 + 12cm^2 = 96cm^2
We could also divide it to one big rectangle and one "negative" rectangle of 10x12 and -8x(10-7), arriving at 10cm*12cm - 8cm*3cm = 120cm^2 - 24cm^2 = 96cm^2
Hello from MrBillDoesMath!
Answer:
4( x + 1.5)^2 + 0
Discussion:
4x^2 + 12x + 9 = => factor "4" from first 2 terms
4 (x^2 + 3x) + 9 = => complete the square, add\subtract (1.5)^2
4(x^2 + 3x + (1.5)^2) - 4 (1.5)^2 + 9 =
4 ( x + 1.5)^2 + ( 9 - 4(1.5)^2) = => as (1.5)^2 = 2.25
4 ( x + 1.5)^2 + ( 9 - 4(2.25)) = => as 4 ( 2.25) = 9
4 ( x+ 1.5)^2 + 0
Thank you,
MrB
Solution:
As given Square L M NO is dilated by a scale factor of two about the center of the square to create square L'M'N'O'.
Original line of Dilation = Along P Q
New Dilated line = P'Q'
As scale factor > 1
1. Image Size > Pre image size
2. The two images will be similar.
3. Length of Dilated Line P' Q' = 2 × Length of PQ
As you can see from the diagram drawn below, Dilated line P'Q' will contain the point P and Q.
All four points P,Q,Q',P' are collinear , lie in the same line.
Option (2) dilated line P'Q' will contain the points P and Q is true.
Answer: What's the exponents?
Step-by-step explanation:
5.2+3.01=8.21
but then there's no exponents that you stated. So it would be 8.21x10^?
If the tens do have exponents above them, add them together.
I hope this answer helps you!
Answer: (-2, 5) and (2, -3)
<u>Step-by-step explanation:</u>
Graph the line y = -2x + 1 (which is in y = mx + b format) by plotting the y-intercept (b = 1) on the y-axis and then using the slope (m = -2) to plot the second point by going down 2 and right 1 unit from the first point:
y - intercept = (0, 1) 2nd point = ( -1, 1).
Graph the parabola y = x² - 2x - 3 by first plotting the vertex and then plotting the y-intercept (or some other point):

vertex = (1, -4) 2nd point (y-intercept) = (0, -3)
<em>see attached</em> - the graphs intersect at two points: (-2, 5) and (2, -3)