Answer:
(3 ± √23 * i) /4
Step-by-step explanation:
To solve this, we can apply the Quadratic Equation.
In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)
Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4
Plugging these values into our equation, we get
x = (-b ± √(b²-4ac))/(2a)
x = (-(-3) ± √(3²-4(2)(4)))/(2(2))
= (3 ± √(9-32))/4
= (3 ± √(-23))/4
= (3 ± √23 * i) /4
Answer:
53
Step-by-step explanation:
20-5y+2x
20-5(-3)+2(9)
20--15+18
cancel out the negative signs
20+15+18
=53
Answer:
7/20
Step-by-step explanation:
3 2/5 3•5+2 17/5 3.4 11 3/20 223/20 11.15 +3.4=11.15
-3.4 -3.4
= 7.75
7.75+3.6 11.15
11.15=11.15
On an investment of $5000 with an interest payment of 5% = $250 at one year. At 3.5 years, the interest payments would total $250 × 3.5 = $875